递归中,调用forEach方法问题
2024-10-07 16:42:19
1 function traverse(objNmae,obj,url){
url = url || objNmae;
if(typeof obj === "object" ){
//for in 方法
for(let i in obj){
url += ("=>"+i);
arguments.callee(i,obj[i],url);
}
//forEach 方法
obj.forEach(function(value,index){
url += ("=>"+index);
arguments.callee(index,value,url);
});
}else if(typeof obj === "string" || typeof obj === "number"){
console.log(url+objNmae+":"+obj);
return;
}
}
for in 方法 和forEach方法,方法的功能是同样的,就是遍历一个对象集,并且输出对象中所有末端元素的路径。
接下来我们对下面的这个对象进行遍历
var itg_data = [{"itg_num":"1200","itg_category":"rew_gold","itg_reward_num":"1","itg_sum_num":"661","itg_place":"","pic":"\/Uploads\/game\/reward\/357203060783037259.png","goods_unit":"\u679a","goods_name":null},{"itg_num":"1400","itg_category":"rew_goods","itg_reward_num":"4","itg_sum_num":"656","itg_place":"fresh","pic":"\/Uploads\/UploadsShop\/2017-07-05\/595c823c86cf7.jpg","goods_unit":"\u679a","goods_name":"\u65e0\u6297\u571f\u9e21\u86cb"},{"itg_num":"1600","itg_category":"rew_gold","itg_reward_num":"2","itg_sum_num":"555","itg_place":"","pic":"\/Uploads\/game\/reward\/357203060783037259.png","goods_unit":"\u679a","goods_name":null},{"itg_num":"1800","itg_category":"rew_goods","itg_reward_num":"8","itg_sum_num":"492","itg_place":"fresh","pic":"\/Uploads\/UploadsShop\/2017-07-05\/595c823c86cf7.jpg","goods_unit":"\u679a","goods_name":"\u65e0\u6297\u571f\u9e21\u86cb"},{"itg_num":"2500","itg_category":"rew_goods","itg_reward_num":"1","itg_sum_num":"555","itg_place":"fresh","pic":"\/Uploads\/UploadsShop\/2017-06-22\/594b602919d9d.jpg","goods_unit":"\u53ea","goods_name":"\u6bcd\u9e21\uff08\u6563\u517b\uff09"}];
for in 方法
但是在这里 forEach方法会报错,
提示最大调用栈大小超过。但是使用for in 就没有这样的问题
由此可见,forEach在递归中因为,有些对象树过深,对导致其堆栈溢出,forEach不适合用在递归中,可以使用for in
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