题解-python-CodeForces 227A

codeforces题目，用python写

本题输入三个点坐标，考察叉积，若大于0则right，小于0则left，等于0则towards

代码：

a = raw_input().split()

b = raw_input().split()

c = raw_input().split()

xa = int(a[0])

ya = int(a[1])

xb = int(b[0])

yb = int(b[1])

xc = int(c[0])

yc = int(c[1])

x1 = xb - xa

x2 = xb - xc

y1 = yb - ya

y2 = yb - yc

res = x1 * y2 - x2 * y1

if res > 0:

    print "RIGHT"

elif res < 0:

    print "LEFT"

else:

    print "TOWARDS"

巴特西

题解-python-CodeForces 227A

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