go语言json转map
2024-09-03 17:09:36
package util
import (
"encoding/json"
"fmt"
)
// json转map函数,通用
func JSONToMap(str string) map[string]interface{} {
var tempMap map[string]interface{}
err := json.Unmarshal([]byte(str), &tempMap)
if err != nil {
panic(err)
}
return tempMap
}
- 如果map中含有数组,并且数组中是数字,需要求和,如何去做
rain = "{\"reqTime\":\"201911141554\",\"startTime\":\"201911141555\",\"endTime\":\"201911141755\",\"series\":[0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.07,0.14,0.32,0.51,0.72,0.92,1.11,1.28,1.41,1.5,1.53,1.5,1.41,1.28,1.11,0.92,0.72,0.51,0.32,0.14,0.07,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0],\"amendNow\":\"多云\",\"amendNowwen\":\"Cloudy\",\"amendNowwcode\":\"01\",\"msg\":\"1小时后会有雪,出门记得带伞\"}"
fmt.Println(rain)
// Json转map, map[string]interface{}
rainMap := util.JSONToMap(rain) //
// 降雨量之和
sum := 0.00
// 遍历map中的series数组,降雨量相加
for _, num := range rainMap["series"].([]interface{}) {
sum += num.(float64) // 这里使用断言
}
fmt.Println(sum) // 结果为 17.490000000000002
如果是多层的json,请参考我的另一篇博客:
(json后的)多层map取值另外感谢网友解决了我的问题:https://www.golangtc.com/t/5628a59fb09ecc56ca000165
最新文章
- 一个表缺失索引发的CPU资源瓶颈案例
- Xcode修改storyboard大小
- call、apply、bind的区别
- Amoeba-mysql读写分离实战
- CSS层次选择器温故-2
- 【读书笔记】iOS-装箱
- Spring MVC 教程,快速入门,深入分析
- [系统集成] Android 自动构建系统
- lenovo X230热键功能
- OpenMP并行化实例----Mandelbrot集合并行化计算
- Windows系统版本判定那些事儿
- golang context
- [leetcode]50. Pow(x, n)求幂
- 20175316 盛茂淞 2018-2019-2 《Java程序设计》实验一 Java开发环境的熟悉 实验报告
- StringBuilder String string.Concat 字符串拼接速度再议
- 前端 websocket用法
- cda转MP3
- part1:15-安装Linux系统到开发板
- Spring AOP注解通过@Autowired,@Resource,@Qualifier,@PostConstruct,@PreDestroy注入属性的配置文件详解
- javascript 理解对象--- 定义多个属性和读取属性的特性