POJ2887(块状链表)
2024-10-21 04:17:07
Big String
Time Limit: 1000MS | Memory Limit: 131072K | |
Total Submissions: 6346 | Accepted: 1525 |
Description
You are given a string and supposed to do some string manipulations.
Input
The first line of the input contains the initial string. You can assume that it is non-empty and its length does not exceed 1,000,000.
The second line contains the number of manipulation commands N (0 < N ≤ 2,000). The following N lines describe a command each. The commands are in one of the two formats below:
- I ch p: Insert a character ch before the p-th character of the current string. If p is larger than the length of the string, the character is appended to the end of the string.
- Q p: Query the p-th character of the current string. The input ensures that the p-th character exists.
All characters in the input are digits or lowercase letters of the English alphabet.
Output
For each Q command output one line containing only the single character queried.
Sample Input
ab
7
Q 1
I c 2
I d 4
I e 2
Q 5
I f 1
Q 3
Sample Output
a
d
e
标准块状链表.
#include"cstdio"
#include"cstring"
#include"cmath"
#include"algorithm"
using namespace std;
const int MAXN=;
char str[MAXN*MAXN];
struct Block_List{
int size,next;
char s[*MAXN];
Block_List()
{
memset(s,,sizeof(s));
size=;
next=-;
} void push(char ch)
{
s[size++]=ch;
} void insert(int pos,char ch)
{
for(int i=size;i>pos;i--)
{
s[i]=s[i-];
}
s[pos]=ch;
size++;
}
}bkl[MAXN]; int bsize,cnt,m;
void Init()
{
gets(str);
scanf("%d",&m);
bsize=(int)sqrt(double(strlen(str)+m));
for(int i=;str[i];i++)
{
if(bkl[cnt].size==bsize)
{
bkl[cnt].next=cnt+;
cnt++;
}
bkl[cnt].push(str[i]);
}
cnt++;
} void Update(int u)
{
if(bkl[u].size<*bsize) return ;
/*
for(int i=bsize;i<bkl[u].size;i++)
{
bkl[cnt].push(bkl[u].s[i]);
}
*/
strcpy(bkl[cnt].s,bkl[u].s+bsize);
bkl[cnt].size=strlen(bkl[u].s)-bsize;
bkl[u].size=bsize;
bkl[cnt].next=bkl[u].next;
bkl[u].next=cnt;
cnt++;
}
void handle()
{
int cas=;
while(++cas<=m)
{
char op[];
scanf("%s",op);
if(op[]=='Q')
{
int pos;
scanf("%d",&pos);
int i;
for(i=;pos>bkl[i].size;i=bkl[i].next)
{
pos-=bkl[i].size;
}
printf("%c\n",bkl[i].s[pos-]);
}
else
{
char ch[];
int pos;
scanf("%s%d",ch,&pos);
int i;
for(i=;pos>bkl[i].size&&bkl[i].next!=-;i=bkl[i].next)
{
pos-=bkl[i].size;
}
bkl[i].insert(pos-,ch[]);
Update(i);
}
}
}
int main()
{
Init();
handle();
return ;
}
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