Kattis - yoda 【字符串】

分析

给出两个串从末尾开始对齐每位对齐后，每一位遍历

如果第一串的那位 < 第二串的那么第一串的那位就删去

如果等于两位都保留

如果大于那么保留第二串的那位

如果最后删完了那一串就输出 YODA

AC代码

#include <cstdio>

#include <cstring>

#include <ctype.h>

#include <cstdlib>

#include <climits>

#include <iostream>

#include <algorithm>

#include <cmath>

#include <deque>

#include <vector>

#include <queue>

#include <string>

#include <map>

#include <stack>

#include <set>

#include <numeric>

#include <sstream>

#include <iomanip>

#include <limits>

using namespace std;

typedef long long LL;

const double PI  = 3.14159265358979323846264338327;

const double E   = 2.718281828459;

const double eps = 1e-6;

const int INF = 0x3f3f3f3f;

const int maxn = 1e9 + 5;

const int MOD  = 1e9 + 7;

int main()

{

    string s1, s2;

    string c1 = "", c2 = "";

    cin >> s1 >> s2;

    int len1 = s1.size(), len2 = s2.size();

    int i, j;

    for (i = len1 - 1, j = len2 - 1; i >= 0 && j >= 0; i--, j--)

    {

        if (s1[i] < s2[j])

            c2 += s2[j];

        else if (s1[i] == s2[j])

        {

            c1 += s1[i];

            c2 += s2[j];

        }

        else

            c1 += s1[i];

    }

    if (i >= 0)

    {

        for ( ; i >= 0; i--)

            c1 += s1[i];

    }

    if (j >= 0)

    {

        for ( ; j >= 0; j--)

            c2 += s2[j];

    }

    if (c1.size())

    {

        for (i = c1.size() - 1; i >= 0; i--)

        {

            if (c1[i] != '0' || (c1[i] == '0' && i == 0))

            {

                cout << c1[i];

                break;

            }

        }

        for (i-- ; i >= 0; i--)

            cout << c1[i];

    }

    else

        cout << "YODA";

    printf("\n");

    if (c2.size())

    {

        for (i = c2.size() - 1; i >= 0; i--)

        {

            if (c2[i] != '0' || (c2[i] == '0' && i == 0))

            {

                cout << c2[i];

                break;

            }

        }

        for (i-- ; i >= 0; i--)

            cout << c2[i];

    }

    else

        cout << "YODA";

    printf("\n");

}

巴特西

Kattis - yoda 【字符串】

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