Rabin_Karp(hash) HDOJ 1711 Number Sequence
2024-08-30 21:05:42
/*
Rabin_Karp:虽说用KMP更好,但是RK算法好理解。简单说一下RK算法的原理:首先把模式串的哈希值算出来,
在文本串里不断更新模式串的长度的哈希值,若相等,则找到了,否则整个模式串的长度的哈希值向右移动一位
*/
/************************************************
* Author :Running_Time
* Created Time :2015-8-5 14:04:26
* File Name :HDOJ_1711.cpp
************************************************/ #include <cstdio>
#include <algorithm>
#include <iostream>
#include <sstream>
#include <cstring>
#include <cmath>
#include <string>
#include <vector>
#include <queue>
#include <deque>
#include <stack>
#include <list>
#include <map>
#include <set>
#include <bitset>
#include <cstdlib>
#include <ctime>
using namespace std; #define lson l, mid, rt << 1
#define rson mid + 1, r, rt << 1 | 1
typedef unsigned long long ull;
typedef long long ll;
const int MAXN = 1e6 + ;
const int MAXM = 1e4 + ;
const int INF = 0x3f3f3f3f;
const ull KEY = ;
int a[MAXN], b[MAXM];
int n, m; int match(void) {
ull h = ;
for (int i=; i<m; ++i) h *= KEY;
ull ah = , bh = ;
for (int i=; i<m; ++i) ah = ah * KEY + a[i];
for (int i=; i<m; ++i) bh = bh * KEY + b[i];
for (int i=; i+m<=n; ++i) {
if (ah == bh) return i + ;
if (i + m < n) {
ah = ah * KEY + a[i+m] - a[i] * h;
}
}
return -;
} int main(void) { //HDOJ 1711 Number Sequence
int T; scanf ("%d", &T);
while (T--) {
scanf ("%d%d", &n, &m);
for (int i=; i<n; ++i) scanf ("%d", &a[i]);
for (int i=; i<m; ++i) scanf ("%d", &b[i]);
printf ("%d\n", match ());
} return ;
}
/*
题目链接:http://oj.acm.zstu.edu.cn/JudgeOnline/problem.php?id=4194
给你两个字符串A,B,请输出B字符串在A字符串中出现了几次。
*/
/************************************************
* Author :Running_Time
* Created Time :2015-8-5 14:04:26
* File Name :ZSTU 4194 字符串匹配
************************************************/ #include <cstdio>
#include <algorithm>
#include <iostream>
#include <sstream>
#include <cstring>
#include <cmath>
#include <string>
#include <vector>
#include <queue>
#include <deque>
#include <stack>
#include <list>
#include <map>
#include <set>
#include <bitset>
#include <cstdlib>
#include <ctime>
using namespace std; #define lson l, mid, rt << 1
#define rson mid + 1, r, rt << 1 | 1
typedef unsigned long long ull;
typedef long long ll;
const int MAXN = 1e6 + ;
const int INF = 0x3f3f3f3f;
const ull KEY = ;
char t[MAXN], p[MAXN]; int Rabin_Karp(void) {
int lent = strlen (t);
int lenp = strlen (p);
ull h = ;
for (int i=; i<lenp; ++i) h *= KEY;
ull th = , ph = ; int ret = ;
for (int i=; i<lenp; ++i) th = th * KEY + t[i];
for (int i=; i<lenp; ++i) ph = ph * KEY + p[i];
for (int i=; i+lenp<=lent; ++i) {
if (th == ph) {
ret++;
for (int j=i; j<=i+lenp-; ++j) { //找到了一个模式串,不能再用,整个跳过去
th = th * KEY + t[j+lenp] - t[j] * h;
}
i += lenp - ; continue;
}
if (i + lenp < lent) {
th = th * KEY + t[i+lenp] - t[i] * h;
}
}
return ret;
} int main(void) { //ZSTU 4194 字符串匹配
while (scanf ("%s %s", t, p) == ) {
printf ("%d\n", Rabin_Karp ());
} return ;
}
Rabin_Karp应用
/*
这就是赤裸裸的模板题,只不过用数字而已
*/
/************************************************
* Author :Running_Time
* Created Time :2015-8-9 19:45:40
* File Name :KMP.cpp
************************************************/ #include <cstdio>
#include <algorithm>
#include <iostream>
#include <sstream>
#include <cstring>
#include <cmath>
#include <string>
#include <vector>
#include <queue>
#include <deque>
#include <stack>
#include <list>
#include <map>
#include <set>
#include <bitset>
#include <cstdlib>
#include <ctime>
using namespace std; #define lson l, mid, rt << 1
#define rson mid + 1, r, rt << 1 | 1
typedef long long ll;
const int MAXN = 1e6 + ;
const int INF = 0x3f3f3f3f;
const int MOD = 1e9 + ;
int nex[MAXN];
int s[MAXN], t[MAXN]; void get_nex(int lm) {
int i = , j = -; nex[] = -;
while (i < lm) {
if (j == - || t[j] == t[i]) {
i++; j++; nex[i] = j;
}
else j = nex[j];
}
} int KMP(int ln, int lm) {
get_nex (lm);
int i = , j = ;
while (i < ln) {
while (j != - && s[i] != t[j]) j = nex[j];
i++; j++;
if (j == lm) return (i - j + );
}
return -;
} int main(void) { //HDOJ 1711 Number Sequence
int T; scanf ("%d", &T);
while (T--) {
int ln, lm; scanf ("%d%d", &ln, &lm);
for (int i=; i<ln; ++i) scanf ("%d", &s[i]);
for (int i=; i<lm; ++i) scanf ("%d", &t[i]);
printf ("%d\n", KMP (ln, lm));
} return ;
}
KMP
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