#include<cstdio>

 #include<cstdlib>

 #include<cstring>

 #include<vector>

 #include<cmath>

 #include<sstream>

 #include<iostream>

 using namespace std;

 const double eps = 1e-;

 int hh, mm, ss;

 int gcd(int a, int b)

 {

     return b ==  ? a : gcd(b, a%b);

 }

 void sub(int a, int b, int c, int d)

 { //分数相减（a/b - c/d = (ad-bc)/bd），各种凌乱的特判，注意取绝对值输出

     if(c == ) //c/d = 0，直接输出a/b

     {

         if(b == )  printf("%d", abs(a));

         else        printf("%d/%d", abs(a), abs(b));

         return;

     }

     int t1 = b*d, t2 = a*d - b*c;

     if(t1 ==  || t2 == ) //分子或分子为0，直接输出0

     {

         printf("");

         return;

     }

     int t12 = gcd(t1, t2); //化简

     int tt1 = t1/t12;

     int tt2 = t2/t12;

     if(tt1 == )    printf("%d", abs(tt2));

     else            printf("%d/%d", abs(tt2), abs(tt1));

 }

 void get_ang(double a1, double a2, int t11, int t12, int t21, int t22)

 {

     if(fabs(a1 - a2) < eps) //两角相等

     {

         printf("");

         return ;

     }

     if(fabs(a1 - a2) > ) //注意两角相差大于180度

     {

         if(a1 > a2)

         {

             t11 = t11 - *t12; //大角减360度，然后二者相减去绝对值，这里动手画一下就清楚了

             sub(t11, t12, t21, t22);

         }

         else

         {

             t21 = t21 - *t22;

             sub(t21, t22, t11, t12);

         }

     }

     else if(fabs(a1 - a2) <= )

     {

         if(a1 > a2)

             sub(t11, t12, t21, t22);

         else

             sub(t21, t22, t11, t12);

     }

 }

 void solve()

 {

     int h = hh* + mm* + ss; //化成秒为单位

     int m = mm* + ss;

     int s = ss;

     int ansh1, ansh2, ansm1, ansm2, anss1, anss2; //主要化简成分数计算

     int gh, gm;        //时针化为秒数与120的最大公约数，分针化为秒数与10的最大公约数

     double ah, am, as; //用double比较三针走过的度数大小

     if(h)

     {

         gh = gcd(h, );

         ansh1 = h/gh, ansh2 = /gh;

         ah = (double)ansh1/ansh2;

     }

     else

     {

         ansh1 = , ansh2 = ;

         ah = 0.0;

     }

     if(m)

     {

         gm = gcd(m, );

         ansm1 = m/gm, ansm2 = /gm;

         am = (double)ansm1/ansm2;

     }

     else

     {

         ansm1 = , ansm2 = ;

         am = 0.0;

     }

     if(s)

     {

         anss1 = s*, anss2 = ;

         as = (double)anss1/anss2;

     }

     else

     {

         anss1 = , anss2 = ;

         as = 0.0;

     }

     get_ang(ah, am, ansh1, ansh2, ansm1, ansm2); printf(" ");

     get_ang(ah, as, ansh1, ansh2, anss1, anss2); printf(" ");

     get_ang(am, as, ansm1, ansm2, anss1, anss2); printf(" ");

 }

 int main()

 {

     int T;

     scanf("%d", &T);

     getchar();

     while(T--)

     {

         string str;

         cin >> str;

         for(int i = ; i < str.length(); i++)

             if(str[i] == ':')

                 str[i] = ' '; //方便用stringstream，用这个耗时会比较大，处理方法随意~

         stringstream SS(str);

         SS >> hh;

         SS >> mm;

         SS >> ss;

         if(hh ==  && (mm || ss)) hh -= ;

         else if(hh > ) hh -= ; //24小时制转为12小时

         solve();

         printf("\n");

     }

     return ;

 }