py之循环，函数

2024-10-21 02:53:27

循环

a=1

while a<10:

	print(a)

	a+=1

a=[123,1235,123124,1231]

while a:

	a1=a.pop()

	print(a1)

for a1 in a:

	print(a1)

for i in range(4):

	print(a[i])

for i in range(len(a)):

	print(a[i])

a=[1,2,3,4,5,6,7]

for i in a:

	if i%2==0:

		print(i)

	else:

		continue

		#break

	print(i)

函数

a=1

b=3

def printer():

	print(a)

printer()

def add_ad(a,b):

	print(a+b)

s=add_ad(1,3)

print(s)

def add_ad(a=1,b=3):

	print(a+b)

s=add_ad()

print(s)

s=add_ad(2,b=3)

print(s)

def add(a,*args):

	sum=0

	for i in args:

		sum+=i

	return sum

def add_2(a,**kwargs):

	for arg,val in kwargs.items():

		print(arg,val)

add(1,x=1,y=2)

#参数元组，*args代表自动识别参数的个数，实现变长参数的输入

#**kwargs接受的一个(str=any)的这样的一对值，变成字典保存下来

def add(a,*args):

	sum=0

	op=9

	for i in args:

		sum+=i

	return sum,op

d=add(1,2,4,5)

print(type(d))

print(d)

#for arg, val in dict.items():

#	print(arg, val)

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