G. The jar of divisors

Alice and Bob play the following game. They choose a number N to play with. The rules are as follows:

- They write each number from 1 to N on a paper and put all these papers in a jar.

- Alice plays first, and the two players alternate.

- In his/her turn, a player can select any available number M and remove its divisors including M.

- The person who cannot make a move in his/her turn wins the game.

Assuming both players play optimally, you are asked the following question: who wins the game?

The first line contains the number of test cases T (1  ≤  T  ≤  20). Each of the next T lines contains an integer (1  ≤  N  ≤  1,000,000,000).

Output T lines, one for each test case, containing Alice if Alice wins the game, or Bob otherwise.

 #include <bits/stdc++.h>

 using namespace std;

 inline int read()

 {

     int x=,f=;

     char ch=getchar();

     while(ch<''||ch>'')

     {

         if(ch=='-')

             f=-;

         ch=getchar();

     }

     while(ch>=''&&ch<='')

     {

         x=x*+ch-'';

         ch=getchar();

     }

     return x*f;

 }

 inline void write(int x)

 {

     if(x<)

     {

         putchar('-');

         x=-x;

     }

     if(x>)

         write(x/);

     putchar(x%+'');

 }

 int main()

 {

     int T;

     T=read();

     while(T--)

     {

         int n;

         n=read();

         if(n>)

             printf("Alice\n");

         else printf("Bob\n");

     }

     return ;

 }