function overloading/ declare function

Declare a function

To declare a function without identifying the argument list, you can do it in this way:

void say hello(...);

here, you use three point (...) to indicate that the function have no argument.

function overloading

Keep in mind that the signature, not the function type, enables function overloading. For example, the following two declaration are incompatible:

long gronk (int n, float m);　　　#1　//same signature

double gronk(int n, float m);　　#2　//hence not allowed

why, for example, if this is possible:

int hel=0;

float haa=3;

gronk(hel, haa); //which function to use, #1 or #2, it is conflict.

therefore, C++ doesn't allow you to overload gronk() in this fashion. You can have different return type, but only if the signature are also different, for example:

long gronk(int n, float m);

double gronk(double n, double m);　　//now it is allowed

巴特西

function overloading/ declare function

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