1、2、3题的运算符规则，把规则代进去即可

逻辑运算符

1.and 并且, 两边同时为True,结果才是True. 有一个是False. 结果是False

2.or 或者, 两边有一个是True. 结果就是True.

3.not 非True既False, 非False既True

运算顺序: () > not > and > or

True：非零

False：零

x or y:

    当x是非零， 返回x

    当x是零， 返回y

【and和or相反】

x and y:

    当x是非零， 返回y

    当x是零， 返回x

4.使用while循环输出1-10，除了7不打印


三种方法可以实现


count = 1


while count <= 10:


if count == 7:


pass


else:


print(count)


count +=1

count = 1


while count <= 10:


if count != 7:


print(count)


count +=1

count = 1


while count <= 10:


if count == 7:


count +=1


continue


print(count)


count +=1

5.猜年龄，猜对显示正确，猜错显示“你太笨了”


n = 0


age = 22

while n < 3:


n +=1


_age = int(input('Age：'))


if age == _age:


print('猜对了')


break


elif age > _age:


print('应该更大点')


elif age < _age:


print('应该更小点')


else:


print('你太笨了')

6.求1-100的和


n = 0


for i in range(1,101):


n += i


print(n)

n = 0


suma = 0


while n < 100:


n += 1


suma += n        #累加运算


print(suma)

7.输出1-100内的所有奇数


8.输出1-100内的所有偶数


count = 1


while count <=100:


if count %2 == 0:       #能除尽为偶数，除不尽为奇数；或用range()


print(count)


count +=1

9.求1-2+3-4+5...99的所有数的和


count = 1


suma = 0        #0+1-2+3...


while count <=99:


if count %2 == 1:   #奇数


suma = suma + count


else:   #偶数


suma = suma - count


count +=1


print(suma)

count = 1


sama = 0        #0+1-2+3...


while count <=99:


if count %2 !=0:    #奇数


sama = sama + count


if count %2 ==0:    #偶数


sama = sama - count


count +=1


print(sama)

10.用户登录（三次输错机会）且每次输错时显示剩余错误次数（提示：使用字符串格式化）


count = 1


username = 'byh'


password = 123

while count <=3:


_username = input('Username:')


_password = int(input('Password:'))


if _username == username and _password == password:


print("Welcome %s login!" %(username))


break


else:


print('Sorry, username or passowrd error. Still try %d' %(3-count))


count += 1

11.判断广告标语：含 "最 第一 稀缺 国家级" 的为不合法


gd = input("请输入你的广告标语：")


if '最' in gd or '第一' in gd or '稀缺' in gd or '国家级' in gd:


print('广告标语不合法')


else:


print('广告标语合法')

lst = ["最", "第一", "稀缺", "国家级"]


def func():


content = input('输入判断广告标语：')


for i in lst:


if i in content:


ret = '广告标语不合法'


return ret


else:


return '广告标语合法'


ret = func()


print(ret)

12.输入一个数，判断这个数是几位数


count = 0


number = int(input("Number:"))


while number >= 1:


number //=10


count +=1


print(count)

sama = ''


count = 0


nu = input("Input number:").strip()


for i in nu:


sama += i


count +=1


print(count)

13.质数（只能被1和自身整除）


思路：从2开始除，一直除到n-1。数字自身-1


n = int(input('请输入一个数：'))


if n == 1:


print("1不是质数")


else:


count = 2


while count <= n-1:


if n % count == 0:


print("这不是质数")


break


count += 1


else:


print("这是质数")

n = int(input('请输入一个数：'))


for i in range(2,n):


if n%i ==0:


print("你不是一个质数")


break


else:


print("你是一个质数")