CodeForces - 1003-B-Binary String Constructing (规律+模拟)

You are given three integers aa, bb and xx. Your task is to construct a binary string ssof length n=a+bn=a+b such that there are exactly aa zeroes, exactly bb ones and exactly xx indices ii (where 1≤i<n1≤i<n) such that si≠si+1si≠si+1. It is guaranteed that the answer always exists.

For example, for the string "01010" there are four indices ii such that 1≤i<n1≤i<n and si≠si+1si≠si+1 (i=1,2,3,4i=1,2,3,4). For the string "111001" there are two such indices ii (i=3,5i=3,5).

Recall that binary string is a non-empty sequence of characters where each character is either 0 or 1.

Input

The first line of the input contains three integers aa, bb and xx (1≤a,b≤100,1≤x<a+b)1≤a,b≤100,1≤x<a+b).

Output

Print only one string ss, where ss is any binary string satisfying conditions described above. It is guaranteed that the answer always exists.

Examples

Input

2 2 1

Output

Input

3 3 3

Output

Input

5 3 6

Output

01010100

题解：

根据0和1谁的数量大，确定从谁开始，然后n为奇数和偶数再分别判断即可

代码：

#include<iostream>

#include<algorithm>

#include<cstdio>

#include<cstring>

using namespace std;

int main()

{

    int a,b,x,s;

    int m,n;

    cin>>a>>b>>x;

    s=a+b;

    if(a>b)

	{

	m=0;

	n=1;

    }

    else

	{

	 m=1;

	 n=0;

	 swap(a,b);

	 }

    for(int i=0;i<x/2;i++) {cout<<m<<n;a--,b--;}

    if(x%2==0){

        while(b--) cout<<n;

        while(a--) cout<<m;

    }

    else{

        while(a--) cout<<m;

        while(b--) cout<<n;

    }

    return 0;

}

巴特西

CodeForces - 1003-B-Binary String Constructing (规律+模拟)

最新文章

热门文章