1082. Read Number in Chinese (25)

时间限制

400 ms

内存限制

32000 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output "Fu" first if it is negative. For example, -123456789 is read as "Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu". Note:
zero ("ling") must be handled correctly according to the Chinese tradition. For example, 100800 is "yi Shi Wan ling ba Bai".

Input Specification:

Each input file contains one test case, which gives an integer with no more than 9 digits.

Output Specification:

For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.

Sample Input 1:

-123456789

Sample Output 1:

Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu

Sample Input 2:

Sample Output 2:

yi Shi Wan ling ba Bai

简单的模拟。仅仅是过程描写叙述有点啰嗦。

首先这句话什么意思 Note: zero ("ling") must be handled correctly according to the Chinese tradition

什么叫Chinese tradition，事实上就是对0的特殊处理。

【1】尾部的0不发音

【2】多个连续的0，仅仅发一个音

【3】多个不连续的0。都要发音

【4】大于4位的数肯定要发 Wan 音

【5】大于8位的数一定要发 Yi 音

并且还有个规律： Shi Bai Qian 这三个音循环出现。

Ac代码：

// pat-1082.cpp : 定义控制台应用程序的入口点。

//

#include "stdafx.h"

#include "iostream"

#include "string"

#include "algorithm"

#include "vector"

#include "stack"

using namespace std;

stack<string> ans;

string num[]={"ling", "yi" ,"er" , "san" , "si" ,  "wu",  "liu" , "qi",  "ba",  "jiu"};

string pos[]={ "Shi","Bai","Qian", "Wan","Yi" };

int main()

{

	long int n=0;

	bool firstout=true;

	cin>>n;

	if (n==0)

	{

		cout<<"ling";

		goto end;

	}

	if (n<0)

	{

		cout<<"Fu";

		firstout=false;

		n=-(n);

	}

	int cnt=0;

	bool wan_flag=false;

	bool zero=false;

	bool first=true;

	while(n)

	{

	  int temp=n%10;

	  //0 特殊处理

	  if (temp==0)

	  {

		  if (cnt==3)

		  {

			  wan_flag=true;

		  }

		  n/=10;

		  if (!first)

		  {

			  cnt++;

		  }

	      first=false;

		  if (zero)//第一次遇到0

		  {

			  ans.push(num[0]);

			  zero=false;

			  continue;

		  }

		  else

		  {

			  continue;

		  }

	  }

	  zero=true;

	  if(first)//忽略个位

	  {

		    ans.push(num[temp]);//yi er san si ~~~~~

			 n/=10;

			  first=false;

			 continue;

	  }

	 if(cnt<7)

	 {

		 if (wan_flag)

		 {

			 wan_flag=false;

			 ans.push(pos[3]);

		 }

	     ans.push(pos[cnt%4]);//shi bai qian wan

	  }

	 else

     {

	  ans.push(pos[4]);//yi

	 }

	  ans.push(num[temp]);//yi er san si ~~~~~

	  n/=10;

	  cnt++;

	}

	while (!ans.empty())

	{

		string temp=ans.top();

		ans.pop();

		if (firstout)

		{

			firstout=false;

			cout<<temp;

			continue;

		}

		cout<<" "<<temp;

	}

end:	return 0;

}

巴特西

pat解题报告【1082】

1082. Read Number in Chinese (25)

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