实验１　C++函数

一．实验目的：

掌握定义函数的方法、函数实参与形参的对应关系以及“值传递”的方式。
熟悉函数的嵌套调用和递归调用的方法。
熟悉全局变量、局部变量概念和使用方式。

二．实验内容：

运行调试第2章编程示例2-5减法游戏；完成练习题2.5.1，2.5.2和2.5.3；
运行调试第4章编程示例4-3素因数；完成练习题4.3.1，4.3.2，4.3.3；
运行调试第4章编程示例4-5汉诺塔；完成练习题4.5.1，4.5.2。

三．示例代码：

　　1.第2章编程示例2-5减法游戏:

#include <iostream>

using namespace std;

int main() {
int total, n;

cout << "Welcome to NIM. Pick a starting total: ";
cin >> total;
while (true) {

// Pick best response and print results.

if ((total % 3) == 2) {
total = total - 2;
cout << "I am subtracting 2." << endl;
} else {
total--;
cout << "I am subtracting 1." << endl;
}
cout << "New total is " << total << endl;
if (total == 0) {
cout << "I win!" << endl;
break;
}

// Get user's response; must be 1 or 2.

cout << "Enter number to subtract (1 or 2): ";
cin >> n;
while (n < 1 || n > 2) {
cout << "Input must be 1 or 2." << endl;
cout << "Re-enter: " << endl;
cin >> n;
}
total = total - n;
cout << "New total is " << total << endl;
if (total == 0) {
cout << "You win!" << endl;
break;
}
}
system("PAUSE");
return 0;
}

　　2. 第4章编程示例4-3素因数：

#include <math.h>
#include <iostream>
using namespace std;

void get_divisors(int n);

int main() {
int n;

cout << "Enter a number and press ENTER: ";
cin >> n;

get_divisors(n);

cout << endl;
system("PAUSE");
return 0;
}

// Get divisors function
// This function prints all the divisors of n,
// by finding the lowest divisor, i, and then
// rerunning itself on n/i, the remaining quotient.

void get_divisors(int n) {
int i;
double sqrt_of_n = sqrt((double) n);

for (i = 2; i <= sqrt_of_n; i++)
if (n % i == 0) { // If i divides n evenly,
cout << i << ", "; // Print i,
get_divisors(n / i); // Factor n/i,
return; // and exit.
}

// If no divisor is found, then n is prime;
// Print n and make no further calls.

cout << n;
}

　　3.第4章编程示例4-5汉诺塔：

#include <cstdlib>
#include <iostream>

using namespace std;
void move_rings(int n, int src, int dest, int other);

int main()
{
int n = 3; // Stack is 3 rings high

move_rings(n, 1, 3, 2); // Move stack 1 to stack 3
system("PAUSE");
return 0;
}

void move_rings(int n, int src, int dest, int other) {
if (n == 1) {
cout << "Move from "<< src <<" to "<< dest << endl;
} else {
move_rings(n - 1, src, other, dest);
cout << "Move from "<< src <<" to "<< dest << endl;
move_rings(n - 1, other, dest, src);
}
}

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实验１　C++函数

一．实验目的：

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巴特西

实验１ C++函数

一．实验目的：

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实验１　C++函数