Problem Description

Give a time.(hh:mm:ss)。you should answer the angle between any two of the minute.hour.second hand

Notice that the answer must be not more 180 and not less than 0

 

Input

There are T(1≤T≤104) test
cases

for each case,one line include the time



0≤hh<24,0≤mm<60,0≤ss<60

 

Output

for each case,output there real number like A/B.(A and B are coprime).if it's an integer then just print it.describe the angle between hour and minute,hour and second hand,minute and second hand.

 

Sample Input

4

00:00:00

06:00:00

12:54:55

04:40:00

 

Sample Output

0 0 0

180 180 0

1391/24 1379/24 1/2

100 140 120 
这是一道简单模拟。但我做了挺长时间，果然模拟题还是非常弱啊。。这里注意尽量不要涉及小数，由于会影响精度。




#include<iostream>

#include<stdio.h>

#include<stdlib.h>

#include<string.h>

#include<math.h>

#include<vector>

#include<map>

#include<set>

#include<queue>

#include<stack>

#include<string>

#include<algorithm>

using namespace std;

int c[10][4],e,f;

int gcd(int a, int b){ return a == 0 ? b : gcd(b % a, a); }

void jian(int a,int b,int c,int d){

	int i,j,t1,t2,t;

	t1=a*d-b*c;

	t2=b*d;

	t=gcd(t2,t1);

	e=t1/t;

	f=t2/t;

}

int main()

{

	int h,m,t,s,n,i,j,T,x2,y2,x3,y3;

	char c1,c2;

	double b1,b2,b3;

	scanf("%d",&T);

	while(T--)

	{

		scanf("%d:%d:%d",&h,&m,&s);

		if(h>=12)h-=12;

		t=h*3600+m*60+s;

		c[1][1]=t;

		c[1][2]=120;

		c[2][1]=m*60+s;

		c[2][2]=10;

		c[3][1]=s*6;

		c[3][2]=1;

		e=f=0;

		jian(c[1][1],c[1][2],c[2][1],c[2][2]);

		if(e*f>0){

			e=f=0;

			jian(c[1][1],c[1][2],c[2][1],c[2][2]);

			if(e>f*180)jian(360,1,e,f);

			if(f==1)printf("%d ",e);

			else printf("%d/%d ",e,f);

		}

		else{

			e=f=0;

			jian(c[2][1],c[2][2],c[1][1],c[1][2]);

			if(e>f*180)jian(360,1,e,f);

			if(f==1)printf("%d ",e);

			else printf("%d/%d ",e,f);

		}

		e=f=0;

		jian(c[1][1],c[1][2],c[3][1],c[3][2]);

		if(e*f>0){

			e=f=0;

			jian(c[1][1],c[1][2],c[3][1],c[3][2]);

			if(e>f*180)jian(360,1,e,f);

			if(f==1)printf("%d ",e);

			else printf("%d/%d ",e,f);

		}

		else{

			e=f=0;

			jian(c[3][1],c[3][2],c[1][1],c[1][2]);

			if(e>f*180)jian(360,1,e,f);

			if(f==1)printf("%d ",e);

			else printf("%d/%d ",e,f);

		}

		e=f=0;

		jian(c[2][1],c[2][2],c[3][1],c[3][2]);

		if(e*f>0){

			e=f=0;

			jian(c[2][1],c[2][2],c[3][1],c[3][2]);

			if(e>f*180)jian(360,1,e,f);

			if(f==1)printf("%d ",e);

			else printf("%d/%d ",e,f);

		}

		else{

			e=f=0;

			jian(c[3][1],c[3][2],c[2][1],c[2][2]);

			if(e>f*180)jian(360,1,e,f);

			if(f==1)printf("%d ",e);

			else printf("%d/%d ",e,f);

		}

		printf("\n");

	}

	return 0;

}