C#LeetCode刷题之#674-最长连续递增序列（ Longest Continuous Increasing Subsequence）

问题

给定一个未经排序的整数数组，找到最长且连续的的递增序列。

输入: [1,3,5,4,7]

输出: 3

解释: 最长连续递增序列是 [1,3,5], 长度为3。尽管 [1,3,5,7] 也是升序的子序列, 但它不是连续的，因为5和7在原数组里被4隔开。

输入: [2,2,2,2,2]

输出: 1

解释: 最长连续递增序列是 [2], 长度为1。

注意：数组长度不会超过10000。

Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).

Input: [1,3,5,4,7]

Output: 3

Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.

Input: [2,2,2,2,2]

Output: 1

Explanation: The longest continuous increasing subsequence is [2], its length is 1.

Note: Length of the array will not exceed 10,000.

示例

public class Program {

    public static void Main(string[] args) {

        int[] nums = null;

        nums = new int[] { 1, 3, 5, 7 };

        var res = FindLengthOfLCIS(nums);

        Console.WriteLine(res);

        Console.ReadKey();

    }

    private static int FindLengthOfLCIS(int[] nums) {

        //没什么好说的，后面比前面大就计数，用max记录最大的连续的的递增序列

        if(nums.Length == 0) return 0;

        int count = 0, max = 0;

        for(int i = 0; i < nums.Length - 1; i++) {

            if(nums[i + 1] > nums[i]) {

                count++;

            } else {

                max = Math.Max(max, count);

                count = 0;

            }

        }

        max = Math.Max(max, count);

        return max + 1;

    }

}

以上给出1种算法实现，以下是这个案例的输出结果：

分析：

显而易见，以上算法的时间复杂度为： $O(n)$ 。

巴特西

C#LeetCode刷题之#674-最长连续递增序列（ Longest Continuous Increasing Subsequence）

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