Chrome自带恐龙小游戏的源码研究(五)

　　在上一篇《Chrome自带恐龙小游戏的源码研究(四)》中实现了障碍物的绘制及移动，从这一篇开始主要研究恐龙的绘制及一系列键盘动作的实现。

会眨眼睛的恐龙

　　在游戏开始前的待机界面，如果仔细观察会发现恐龙会时不时地眨眼睛。这是通过交替绘制这两个图像实现的：

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可以通过一张图片来了解这个过程：

　　为实现图片的切换，需要一个计时器timer，并且需要知道两张图片切换的时间间隔msPerFrame。当计时器timer的时间大于切换的时间间隔msPerFrame时，将图片切换到下一张，到达最后一张时又从第一张开始，如此反复。下面是实现代码：

 Trex.config = {

     BLINK_TIMING:3000,  //眨眼间隔

     WIDTH: 44,        //站立时宽度

     WIDTH_DUCK: 59,    //闪避时宽度

     HEIGHT: 47,    //站立时高度

     BOTTOM_PAD: 10,

     MIN_JUMP_HEIGHT: 30 //最小起跳高度

 };

 //状态

 Trex.status = {

     CRASHED: 'CRASHED',    //与障碍物发生碰撞

     DUCKING: 'DUCKING',    //闪避

     JUMPING: 'JUMPING',    //跳跃

     RUNNING: 'RUNNING',    //跑动

     WAITING: 'WAITING'    //待机

 };

 //元数据(metadata)，记录各个状态的动画帧和帧率

 Trex.animFrames = {

     WAITING: {//待机状态

         frames: [44, 0],//动画帧x坐标在44和0之间切换，由于在雪碧图中的y坐标是0所以不用记录

         msPerFrame: 1000 / 3    //一秒3帧

     },

     RUNNING: {

         frames: [88, 132],

         msPerFrame: 1000 / 12

     },

     CRASHED: {

         frames: [220],

         msPerFrame: 1000 / 60

     },

     JUMPING: {

         frames: [0],

         msPerFrame: 1000 / 60

     },

     DUCKING: {

         frames: [262, 321],

         msPerFrame: 1000 / 8

     }

 };

 function Trex(canvas,spritePos){

     this.canvas = canvas;

     this.ctx = canvas.getContext('2d');

     this.spritePos = spritePos; //在雪碧图中的位置

     this.xPos = 0;  //在画布中的x坐标

     this.yPos = 0;  //在画布中的y坐标

     this.groundYPos = 0;    //初始化地面的高度

     this.currentFrame = 0;  //初始化动画帧

     this.currentAnimFrames = [];    //记录当前状态的动画帧

     this.blinkDelay = 0;    //眨眼延迟(随机)

     this.animStartTime = 0; //动画开始的时间

     this.timer = 0; //计时器

     this.msPerFrame = 1000 / FPS;   //默认帧率

     this.config = Trex.config;  //拷贝一个配置的副本方便以后使用

     this.jumpVelocity = 0;  //跳跃的初始速度

     this.status = Trex.status.WAITING;  //初始化默认状态为待机状态

     //为各种状态建立标识

     this.jumping = false;    //角色是否处于跳跃中

     this.ducking = false;    //角色是否处于闪避中

     this.reachedMinHeight = false;  //是否到达最小跳跃高度

     this.speedDrop = false; //是否加速降落

     this.jumpCount = 0;     //跳跃次数

     this.init();

 }

　　首先还是和以往一样，对Trex这个构造函数进行基本的配置，然后在原型链中添加操作方法：

 Trex.prototype = {

     init:function() {

         this.groundYPos = DEFAULT_HEIGHT - this.config.HEIGHT - this.config.BOTTOM_PAD;

         this.yPos = this.groundYPos;

         //计算出最小起跳高度

         this.minJumpHeight = this.groundYPos - this.config.MIN_JUMP_HEIGHT;

         this.draw(0,0);

         this.update(0,Trex.status.WAITING);

     },

     setBlinkDelay:function () {

         //设置随机眨眼间隔时间

         this.blinkDelay = Math.ceil(Math.random() * Trex.config.BLINK_TIMING);

     },

     update:function (deltaTime,opt_status) {

         this.timer += deltaTime;

         if(opt_status) {

             this.status = opt_status;

             this.currentFrame = 0;

             //得到对应状态的帧率 e.g. WAITING 1000ms / 3fps = 333ms/fps

             this.msPerFrame = Trex.animFrames[opt_status].msPerFrame;

             //对应状态的动画帧 e.g. WAITING [44,0]

             this.currentAnimFrames = Trex.animFrames[opt_status].frames;

             if(opt_status === Trex.status.WAITING) {

                 //开始计y时

                 this.animStartTime = getTimeStamp();

                 //设置延时

                 this.setBlinkDelay();

             }

         }

         //计时器超过一帧的运行时间，切换到下一帧

         if (this.timer >= this.msPerFrame) {

             this.currentFrame = this.currentFrame === this.currentAnimFrames.length - 1 ?

                  0 : this.currentFrame + 1;

             this.timer = 0; //重置计时器

         }

         //待机状态

         if(this.status === Trex.status.WAITING) {

             //执行眨眼动作

             this.blink(getTimeStamp());

         }

     },

     blink:function (time) {

         var deltaTime = time - this.animStartTime;

         if(deltaTime >= this.blinkDelay) {

             this.draw(this.currentAnimFrames[this.currentFrame],0);

             if (this.currentFrame === 1) {//0闭眼 1睁眼

                 //设置新的眨眼间隔时间

                 this.setBlinkDelay();

                 this.animStartTime = time;

             }

         }

     },

     draw:function (x,y) {

         var sourceX = x;

         var sourceY = y;

         var sourceWidth = this.ducking && this.status != Trex.status.CRASHED ?

             this.config.WIDTH_DUCK : this.config.WIDTH;

         var sourceHeight = this.config.HEIGHT;

         sourceX += this.spritePos.x;

         sourceY += this.spritePos.y;

         this.ctx.drawImage(imgSprite,

             sourceX, sourceY,

             sourceWidth, sourceHeight,

             this.xPos, this.yPos,

             this.config.WIDTH, this.config.HEIGHT);

     }

 };

　　先来看update方法中的这段代码：

 if (this.timer >= this.msPerFrame) {

     this.currentFrame = this.currentFrame === this.currentAnimFrames.length - 1 ?

          0 : this.currentFrame + 1;

     this.timer = 0;

 }

　　这段代码实现了两个帧之间的切换，但如果只是单纯地以相同时间间隔来切换两张图片，那么得到的效果是不正确的，会出现频繁眨眼的情况。而实际情况是，闭眼只是一瞬间，睁开眼睛的时间则比较长。Chrome开发人员非常巧妙地解决了这个问题：

 blink:function (time) {

     var deltaTime = time - this.animStartTime;

     if(deltaTime >= this.blinkDelay) {

         this.draw(this.currentAnimFrames[this.currentFrame],0);

         if (this.currentFrame === 1) {//0闭眼 1睁眼

             //设置新的眨眼间隔时间

             this.setBlinkDelay();

             this.animStartTime = time;

         }

     }

 }

　　只要计时器没有超过blinkDelay就不绘制新的图片，这样图片就会停留在上一次绘制的状态，恐龙此时是睁着眼睛的。当时间超过了blinkDelay，即执行眨眼的时间到了，这时会绘制this.currentFrame这一帧。如果这一帧是0(闭眼)，由于之前设置了this.timer >= this.msPerFrame时会切换帧，当时间再次超过blinkDelay时，这时就会绘制帧1(睁眼)，我们看到的效果就是眼睛闭上只有一瞬然后立刻睁开了。如果当前帧是1(睁眼)，重新设置blinkDelay，于是在deltaTime没有超过重新设置blinkDelay的情况下，都不会绘制新图片(始终保持在帧1(睁眼))，这样我们看到的效果就是睁眼的时间稍长。

下面是运行后的效果：

// this.bumpThreshold ? this.dimensions.WIDTH : 0;
},
draw:function() {
this.ctx.drawImage(imgSprite,
this.sourceXPos[0], this.spritePos.y,
this.dimensions.WIDTH, this.dimensions.HEIGHT,
this.xPos[0],this.yPos,
this.dimensions.WIDTH,this.dimensions.HEIGHT);

this.ctx.drawImage(imgSprite,
this.sourceXPos[1], this.spritePos.y,
this.dimensions.WIDTH, this.dimensions.HEIGHT,
this.xPos[1],this.yPos,
this.dimensions.WIDTH,this.dimensions.HEIGHT);

},
updateXPos:function(pos,increment) {
var line1 = pos,
line2 = pos === 0 ? 1 : 0;

this.xPos[line1] -= increment;
this.xPos[line2] = this.xPos[line1] + this.dimensions.WIDTH;

if(this.xPos[line1] = this.msPerFrame) {
this.currentFrame = this.currentFrame === this.currentAnimFrames.length - 1 ?
0 : this.currentFrame + 1;
this.timer = 0;
}

//待机状态
if(this.status === Trex.status.WAITING) {
//执行眨眼动作
this.blink(getTimeStamp());
}
},
blink:function (time) {
var deltaTime = time - this.animStartTime;

if(deltaTime >= this.blinkDelay) {
this.draw(this.currentAnimFrames[this.currentFrame],0);

if (this.currentFrame === 1) {//0闭眼 1开眼
//设置新的眨眼间隔时间
this.setBlinkDelay();
this.animStartTime = time;
}
}
},
draw:function (x,y) {
var sourceX = x;
var sourceY = y;
var sourceWidth = this.ducking && this.status != Trex.status.CRASHED ?
this.config.WIDTH_DUCK : this.config.WIDTH;
var sourceHeight = this.config.HEIGHT;
sourceX += this.spritePos.x;
sourceY += this.spritePos.y;

this.ctx.drawImage(imgSprite,
sourceX, sourceY,
sourceWidth, sourceHeight,
this.xPos, this.yPos,
this.config.WIDTH, this.config.HEIGHT);
}
};

window.onload = function () {
var h = new HorizonLine(c,spriteDefinition.HORIZON);
var trex = new Trex(c,spriteDefinition.TREX);
var startTime = 0;
var deltaTime;
var speed = 3;

(function draw(time) {
time = time || 0;
deltaTime = time - startTime;
trex.update(deltaTime);
startTime = time;
requestAnimationFrame(draw,c);
})();
};
// ]]>

巴特西

Chrome自带恐龙小游戏的源码研究(五)

会眨眼睛的恐龙

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