JS取得不同连接的地址，并打开新窗口

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN"

"http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">

<head>

  <meta http-equiv="content-type" content="text/html; charset=utf-8" />

  <title>Example</title>

<script type="text/JavaScript">

window.onload = function() {

  if (!document.getElementsByTagName) return false;

  var lnks = document.getElementsByTagName("a");

  for (var i=0; i<lnks.length; i++) {

    if (lnks[i].getAttribute("class") == "popup") {

      lnks[i].onclick = function() {

        popUp(this.getAttribute("href"));

        return false;

      }

    }

  }

}

function popUp(winURL) {

  window.open(winURL,"popup","width=320,height=480");

}

</script>

</head>

<body>

<a href="http://www.example.com/" class="popup">Example</a>

</body>

</html>

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JS取得不同连接的地址，并打开新窗口

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