A + B

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题意分析

讲字符串和数字用map对应即可

代码总览

/*

    Title:HDOJ.1228

    Author:pengwill

    Date:2016-11-21

*/

#include <iostream>

#include <map>

#include <string>

using namespace std;

typedef map<string,int> mmp;

mmp p;

mmp::iterator iter1,iter2,iter3;

string s1,s2,s3,s4,s5,s6;

int main()

{

    cin.sync_with_stdio(false);

    cin.tie(0);

    p["zero"] = 0;

p["one"] = 1;

p["two"] = 2;

p["three"] = 3;

p["four"] = 4;

p["five"] = 5;

p["six"] = 6;

p["seven"] = 7;

p["eight"] = 8;

p["nine"] = 9;

    while(cin>>s1>>s2>>s3){

        if(s2.compare("+") == 0){

            if(s1.compare("zero")==0 && s3.compare("zero")==0){

                break;

            }else{

                cin>>s4;

                if(s4.compare("=") == 0){

                    iter1 = p.find(s1);iter2 = p.find(s3);

                    cout<<iter1->second + iter2->second<<endl;

                }else{

                    int a;

                    cin>>s5;

                    iter3 = p.find(s1);

                    iter1 = p.find(s3);iter2 = p.find(s4);

                    a = iter1->second * 10 + iter2->second;

                    cout<<a+ iter3->second <<endl;

                }

            }

        }else{

            int a,b;

            iter1 = p.find(s1);iter2 = p.find(s2);

            a = iter1->second * 10 + iter2->second;

            cin>>s1>>s2;

            if(s2.compare("=") == 0){

               // cout<<s2<<endl;

                iter3 = p.find(s1);

                b = iter3->second;

               // cout<<s1<<endl;

               // cout<<iter3->second<<endl;

                cout<<a + b<<endl;;

            }else{

                cin>>s3;

                iter1 = p.find(s1);iter2 = p.find(s2);

                b = iter1->second * 10 + iter2->second;

                cout<<a+b<<endl;

            }

        }

    }

    return 0;

}