A + B Again

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 15772 Accepted Submission(s): 6847

Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming.

Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.

Easy ? AC it !

Input

The input contains several test cases, please process to the end of the file.

Each case consists of two hexadecimal integers A and B in a line seperated by a blank.

The length of A and B is less than 15.

Output

For each test case,print the sum of A and B in hexadecimal in one line.

Sample Input

+A -A

+1A 12

1A -9

-1A -12

1A -AA

Sample Output

0

2C

11

-2C

-90

Author

linle

Source

校庆杯Warm Up

1.%I64X 输入

2.%I64X 不能输出负数

3.%I64O 也不能输出负数

4.如果x 为小写输出的16进制为小写，为大写，输出大写

#include <cstdio>

#include <cstdlib>

#include <cmath>

#include <cstring>

#include <ctime>

#include <algorithm>

#include <iostream>

#include <sstream>

#include <string>

#define oo 0x13131313

using namespace std;

int main()

{

	long long A;long long B;

	while(scanf("%I64O%I64O",&A,&B)!=EOF)

	{

		long long C=A+B;

	//	if(C<0)

	//	printf("-%I64X\n",-C);

		 printf("%I64o\n",C);

	}

	return 0;

}

巴特西

【进制问题】【HDU2056】A + B Again

A + B Again

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