【AIM Tech Round 5 (rated, Div. 1 + Div. 2) B】Unnatural Conditions

在这里输入题意

【题解】

让a+b的和为100000000...0这样的形式就好了
这样s(a+b)=1=1)
然后至于s(a)>=n和s(b)>=n
随便写个a=1111111...112然后b=8888888...888这样就好

【代码】

#include <bits/stdc++.h>

#define LL long long

#define rep1(i,a,b) for (int i = a;i <= b;i++)

#define rep2(i,a,b) for (int i = a;i >= b;i--)

#define all(x) x.begin(),x.end()

#define pb push_back

#define lson l,mid,rt<<1

#define ri(x) scanf("%d",&x)

#define rl(x) scanf("%lld",&x)

#define rs(x) scanf("%s",x)

#define rson mid+1,r,rt<<1|1

using namespace std;

const double pi = acos(-1);

const int dx[4] = {0,0,1,-1};

const int dy[4] = {1,-1,0,0};

const int N = 200;

char s[N+10][N+10];

int n,m;

int main(){

	#ifdef LOCAL_DEFINE

	    freopen("rush_in.txt", "r", stdin);

	#endif

	rep1(i,1,2000) cout<<8;cout<<endl;

    rep1(i,1,1999) cout<<1;cout<<2<<endl;

	return 0;

}

巴特西

【AIM Tech Round 5 (rated, Div. 1 + Div. 2) B】Unnatural Conditions

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