[Typescript] Promise based delay function using async / await

Learn how to write a promise based delay function and then use it in async await to see how much it simplifies code over setTimeout.

Lets say you want to call a function after 1s, 2s, 3s. You can use setTimeout, or you can wrap it up into a simple delay function that works with async/await

const delay = (ms) => new Promise(res => setTimeout(res, ms));

const runAsync = async (cb) => {

  await delay();

  cb('1s')

  await delay();

  cb('2s')

  await delay();

  cb('3s')

} 

runAsync((m) => { console.log(m)})

or normal promise:

const delay = ms => new Promise(res => setTimeout(res, ms));

const runAsync = cb => {

  Promise.resolve()

    .then(() => {

      cb("1s");

      return delay(1000);

    })

    .then(() => {

      cb("2s");

      return delay(1000);

    })

    .then(() => {

      cb("3s");

      return delay(1000);

    });

};

runAsync(m => {

  console.log(m);

});

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[Typescript] Promise based delay function using async / await

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