C. Anya and Ghosts
time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Anya loves to watch horror movies. In the best traditions of horror, she will be visited by m ghosts tonight. Anya has lots of candles prepared for the visits, each candle can produce light for exactly t seconds. It takes the girl one second to light one candle. More formally, Anya can spend one second to light one candle, then this candle burns for exactly t seconds and then goes out and can no longer be used.

For each of the m ghosts Anya knows the time at which it comes: the i-th visit will happen wi seconds after midnight, all wi's are distinct. Each visit lasts exactly one second.

What is the minimum number of candles Anya should use so that during each visit, at least r candles are burning? Anya can start to light a candle at any time that is integer number of seconds from midnight, possibly, at the time before midnight. That means, she can start to light a candle integer number of seconds before midnight or integer number of seconds after a midnight, or in other words in any integer moment of time.

Input

The first line contains three integers m, t, r (1 ≤ m, t, r ≤ 300), representing the number of ghosts to visit Anya, the duration of a candle's burning and the minimum number of candles that should burn during each visit.

The next line contains m space-separated numbers wi (1 ≤ i ≤ m, 1 ≤ wi ≤ 300), the i-th of them repesents at what second after the midnight the i-th ghost will come. All wi's are distinct, they follow in the strictly increasing order.

Output

If it is possible to make at least r candles burn during each visit, then print the minimum number of candles that Anya needs to light for that.

If that is impossible, print  - 1.

Sample test(s)
Input
1 8 3
10
Output
3
Input
2 10 1
5 8
Output
1
Input
1 1 3
10
Output
-1
Note

Anya can start lighting a candle in the same second with ghost visit. But this candle isn't counted as burning at this visit.

It takes exactly one second to light up a candle and only after that second this candle is considered burning; it means that if Anya starts lighting candle at moment x, candle is buring from second x + 1 to second x + t inclusively.

In the first sample test three candles are enough. For example, Anya can start lighting them at the 3-rd, 5-th and 7-th seconds after the midnight.

In the second sample test one candle is enough. For example, Anya can start lighting it one second before the midnight.

In the third sample test the answer is  - 1, since during each second at most one candle can burn but Anya needs three candles to light up the room at the moment when the ghost comes.

模拟一下,然后肯定是在这个鬼之前点灯好,越晚点灯越好

#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
#define maxn 1001
const int inf=0x7fffffff; //无限大
int flag[];
int a[maxn];
int kiss[];
int main()
{
int m,t,r;
cin>>m>>t>>r;
for(int i=;i<m;i++)
{
cin>>a[i];
flag[a[i]+]=;
}
if(r>t)
cout<<"-1"<<endl;
else
{
sort(a,a+m);
for(int i=;i<;i++)
{
if(flag[i]==)
{
int check=;
for(int j=i-;j>=i-t;j--)
{
if(kiss[j]==)
check++;
}
for(int j=i-;j>=i-(r-check);j--)
kiss[j]=;
}
}
int ans=;
for(int i=;i<;i++)
{
if(kiss[i]==)
ans++;
}
cout<<ans<<endl;
}
}

最新文章

  1. [Scala] Scala基础知识
  2. 加速android源码编译
  3. Java 线程通信
  4. [转载]ExtJs4 笔记(12) Ext.toolbar.Toolbar 工具栏、Ext.toolbar.Paging 分页栏、Ext.ux.statusbar.StatusBar 状态栏
  5. typeof关键字简介 -rtti
  6. (KEIL)MDK5安装与JLINK问题解决方法(支持代码自动补全)
  7. 编程之美 两个叶子的节点之间 最大距离 变种 leecode
  8. codevs 1170 双栈排序
  9. 关于Condition Variable的一些思考
  10. Sping--IOC概念
  11. 视频转GIF图
  12. javaScript系列 [04]-javaScript的原型链
  13. Vue中父子组件通讯——组件todolist
  14. 常规DP专题练习
  15. matlab练习程序(马尔可夫聚类MCL)
  16. 搭建vscode+vue环境
  17. 2018-8-16JWTtoken用户登录认证思路分析9502751
  18. python 函数的名称空间及作用域
  19. Python时间系统
  20. c语言指针笔记

热门文章

  1. 用Qemu模拟vexpress-a9 (一) --- 搭建Linux kernel调试环境【转】
  2. iptables NAT规则【转】
  3. Focal Loss笔记
  4. 栈应用之 背包问题(Python 版)
  5. 利用vw+rem实现移动web适配布局
  6. 浮动元素垂直居中,bootstrap栅格布局垂直居中
  7. 调研助力4S店,解码困境谜团
  8. 如何使用django+celery+RabbitMQ实现异步执行
  9. Apache Kylin安装部署
  10. vue-cli中如何集成UEditor 富文本编辑器?