/*

     题意：给出一种方案使得abs (A - G) <= 500，否则输出-1

     贪心：每次选取使他们相差最小的，然而并没有-1:)

 */

 #include <cstdio>

 #include <cstring>

 #include <iostream>

 #include <cmath>

 #include <algorithm>

 using namespace std;

 const int MAXN = 1e6 + ;

 const int INF = 0x3f3f3f3f;

 int main(void)        //Codeforces Round #173 (Div. 2) B. Painting Eggs

 {

 //    freopen ("B.in", "r", stdin);

     int n;

     while (scanf ("%d", &n) == )

     {

         string ans = "";    int sum_a = , sum_g = ;

         for (int i=; i<=n; ++i)

         {

             int x, y;

             scanf ("%d%d", &x, &y);

             if (abs (sum_a + x - sum_g) <= abs (sum_g + y - sum_a))    {ans += "A";    sum_a += x;}

             else    {ans += 'G';    sum_g += y;}

         }

         cout << ans << endl;

     }

     return ;

 }