003_linuxC++之_namespace使用

（一）引入namespace原因：

假如有很多跟人共同完成一项工程，工程中难免会有函数定义一样的名称，不可能一个一个的询问这个函数你定义过了没有，所以引入namespace

 #include <stdio.h>

 #include "person.h"

 #include "dog.h"

 /*global namespace*/

 /*把A::person放入global namespace，以后可以使用person来表示A::person*/

 using namespace A;

 using namespace C;

 int main(int argc,char ** argv)

 {

     /*local namespace*/

     Person per;

     Dog dog;

     per.setName("zhangsan");

     per.setAge();

     per.printInfo();

     dog.setName("lisi");

     dog.setAge();

     dog.printInfo();

     A::printVersion();

     C::printVersion();

     return ;

 }

main.cpp

 #include <stdio.h>

 namespace A{

 class Person{

 private:

     char *name;

     int age;

     char *work;

 public:

     void setName(char *name);

     int setAge(int Age);

     void printInfo(void);

 };

 void printVersion(void);

 }

person.h

 #include <iostream>

 #include "person.h"

 using namespace std;

 namespace A{

 void Person::setName(char *name)

 {

     this->name = name;

 }

 int Person::setAge(int Age)

 {

     if(Age <  || Age > )

     {

         this->age = ;

         return -;

     }

     this->age = Age;

     return ;

 }

 void Person::printInfo(void)

 {

     cout<<"nane = "<<name<<"age = "<<age<<"work = "<<work<<endl;

     //intf("name = %s, age = %d, work = %s\n",name,age,work);

 }

 void printVersion(void)

 {

     cout<<"Person V1, by luxiaoguo"<<endl;

     //intf("Person V1, by luxiaoguo\n");

 }

 }

person.cpp

 namespace C{

 class Dog{

 private:

     char *name;

     int age;

     char *work;

 public:

     void setName(char *name);

     int setAge(int age);

     void printInfo(void);

 };

 void printVersion(void);

 }

dog.h

 #include <stdio.h>

 #include "dog.h"

 namespace C{

 void Dog::setName(char *name)

 {

     this->name = name;

 }

 int Dog::setAge(int Age)

 {

     if(Age <  || Age > )

     {

         this->age = ;

         return -;

     }

     this->age = Age;

     return ;

 }

 void Dog::printInfo(void)

 {

     printf("name = %s, age = %d, work = %s\n",name,age,work);

 }

 void printVersion(void)

 {

     printf("Dog V1, by luxiaoguo\n");

 }

 }

dog.cpp

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003_linuxC++之_namespace使用

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