#DayDayUp,每天进步一千分之一

print("基础为1")

dayup=pow(1.001,365)

#DayDayDown，每天退步一千分之一

daydown=pow(0.999,365)

print("天天向上:{:.2f}\n天天退步:{:.2f}".format(dayup,daydown))

print("努力吧！")

dayfactor=0.005

dayup=pow(1+dayfactor,365)

daydown=pow(1-dayfactor,365)

print("天天向上:{:.2f}\n天天退步:{:.2f}".format(dayup,daydown))

dayfactor=0.01

dayup=pow(1+dayfactor,365)

daydown=pow(1-dayfactor,365)

print("天天向上:{:.2f}\n天天退步:{:.2f}".format(dayup,daydown))

#循环模拟365天的过程

dayup=1.0#基数

dayfactor=0.01#天天向上

for i in range(365):#i表示每一天

    if i%7 in[6,0]:#尾数为6或0即为周末

        dayup=dayup*(1-dayfactor)

    else:

        dayup=dayup*(1+dayfactor)

print("工作日的力量:{:.2f}".format(dayup))

def dayUp(df):#使用def定义一个函数，计算工作日力量,df为Dayfactor

    dayup=1

    for i in range(365):#i表示每一天,这里模拟365天

        if i%7 in[6,0]:#尾数为6或0即为周末

         dayup=dayup*(1-0.01)

    else:

         dayup=dayup*(1+df)

    return dayup

Dayfactor=0.01

while dayUp(Dayfactor)<37.18:#B童鞋与A童鞋比较，试错  while判断条件是否成立，成立时循环执行

   Dayfactor+=0.01

print("工作日努力参数是{:.3f}".format(Dayfactor))