Leetcode 题目整理-4 Longest Common Prefix & Remove Nth Node From End of List

14. Longest Common Prefix

Write a function to find the longest common prefix string amongst an array of strings.

注：这题竟然连个示例都没有，说明特殊情况并不多，就是要找出所有字符串的最长公共前缀。他应该不会超过所有字符串中最短的那个，可以试着找出最短长度n，然后每个都读取和比较n个，并根据情况不断减小那个n.\

 if (strs.size() == )

    {

        return "";

    }

    int n{int(strs.front().size())};

    if (n == )

    {

        return "";

    }

    for (vector<string>::iterator str_i = strs.begin()+; str_i != strs.end(); str_i++)

    {

        if ((*str_i).size() < n)

        {

            n = (*str_i).size();

        }

        int temp{n};//感觉有点儿多余

        for (int i = ; i < n; i++)

        {

            if ((*str_i).at(i) != (*(str_i - )).at(i))

            {

                temp = i;

                break;

            }

        }

        n = temp;

    }

    string longest_prefix(strs.front(),,n);

    return longest_prefix;

19. Remove Nth Node From End of List

Given a linked list, remove the n^th node from the end of list and return its head.

For example,

Given linked list: 1->2->3->4->5, and n = 2.

After removing the second node from the end, the linked list becomes 1->2->3->5.

Note:
Given n will always be valid.
Try to do this in one pass.

注：给出一个链表，把倒数第n个元素移除。听起来很常用的技术，了解一下链表的结构，用处，优势，再来做这个题。

今天关于链表的部分没有完成，明天继续

    int i{  };

    ListNode *temp,*fronter ,*backer,*curNode;

    temp = head;

    //fronter从第一个节点开始向后移动，直到第n个，或者到了结尾

    for (fronter = temp; i < n && !(fronter->next==NULL); fronter = fronter->next,i++);//(*fronter).next)

    if (fronter->next == NULL)//如果是因为到了结尾而结束的循环，那么说明要删除的点在head

    {

        ListNode *tmp = head;

        if (head->next==NULL)//整个链表只有一个节点

            head= ;

        else

            head = head->next;

        return head;

    }

    //如果是因为fornter已经过去n个了，那么这个时候给backer赋值

    curNode = head;

    //二者同时继续向后遍历，直到fronter走到结尾时，删除backer之后的那个节点

    for (; fronter->next != NULL; fronter = fronter->next){

        backer=curNode;

        curNode = curNode->next;

    }

    //删除backer后面的节点

    backer->next = curNode->next;

    return head;

巴特西

Leetcode 题目整理-4 Longest Common Prefix & Remove Nth Node From End of List

14. Longest Common Prefix

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