ajax简单案例

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>

<%

String path = request.getContextPath();

String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";

%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">

<html>

  <head>

    <base href="<%=basePath%>">

    <title>My JSP 'test1.jsp' starting page</title>

    <script type="text/javascript" src="js/jquery-3.3.1.js"></script>

    <script type="text/javascript">

        $(function(){

            $("button").click(function(){

                var param={

                    name:$("#name").val(),

                    age:$("#age").val()

                };

                $.ajax({

                url:"OneServlet",

                data:param,

                beforeSend:function(){

                    $("img").show();

                },

                success:function(data)

                {

                    alert(data);

                },

                complete:function()

                {

                    $("img").hide();

                },

                error:function(XMLHttpRequest,textStatus,errorThrown){

                alert(XMLHttpRequest+" "+textStatus+" "+errorThrown);

                }

            });

            });

        });

    </script>

  </head>

  <body>

    <form action="">

        <input  type="text" id="name"/><br>

        <input  type="text" id="age"/><br>

        <button id="btn">btu</button>

    </form>

    <img src="html/3.jpg" style="display:none;"/>

  </body>

</html>

对应的servlet

package song.yan;

import java.io.IOException;

import java.io.PrintWriter;

import javax.servlet.ServletException;

import javax.servlet.http.HttpServlet;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;

public class OneServlet extends HttpServlet {

    public void doGet(HttpServletRequest request, HttpServletResponse response)

            throws ServletException, IOException {

        response.setContentType("text/html");

        PrintWriter out = response.getWriter();

        String name=request.getParameter("name");

        String age=request.getParameter("age");

        out.print(name+":"+age);

        out.flush();

        out.close();

    }

    public void doPost(HttpServletRequest request, HttpServletResponse response)

            throws ServletException, IOException {

        doGet(request,response);

    }

}

巴特西

ajax简单案例

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