最小树形图模板题……

这种\(O(nm)\)的东西真的能考到么……

#include <bits/stdc++.h>
#define N 60
#define INF 1000000000
using namespace std;
int n, m, nn;
double ai[N], an[N], ci[][N][N], ans;
int bc[N];
int ini[N], vis[N], inc[N], inl[N];
int dfn;
int dfs(int t)
{
vis[t] = dfn;
if (vis[ini[t]] == vis[t])
return ini[t];
else if (vis[ini[t]])
return ;
else return dfs(ini[t]);
} int main()
{
scanf("%d", &n);
for (int i = ; i <= n; ++ i)
for (int j = ; j <= n; ++ j)
ci[][i][j] = INF;
for (int i = ; i <= n; ++ i)
scanf("%lf%d", &ai[i], &bc[i]), an[i] = ai[i], ci[][][i] = ai[i];
scanf("%d", &m);
for (int i = ; i <= m; ++ i)
{
int a, b; double c;
scanf("%d%d%lf", &a, &b, &c);
if (a != b) ci[][a][b] = min(ci[][a][b], c);
an[b] = min(an[b], c);
}
for (int i = ; i <= n; ++ i) ans += an[i] * (bc[i] - );
int tmp = , wh = ; nn = n;
while (wh)
{
wh = ;
for (int i = ; i <= nn; ++ i)
{
double mn = INF;
for (int j = ; j <= nn; ++ j)
if (ci[tmp][j][i] < mn)
mn = ci[tmp][j][i], ini[i] = j;
}
for (int i = ; i <= nn; ++ i) vis[i] = ; vis[] = -;
for (int i = ; i <= nn; ++ i)
if (!vis[i])
{
dfn ++;
int x = dfs(i);
if (x)
{
int tot = ;
wh = ;
for (int j = ; j <= nn; ++ j) inc[j] = ;
for (int j = ini[x]; j != x; j = ini[j]) inc[j] = ; inc[x] = ;
for (int j = ; j <= nn; ++ j) if (!inc[j]) inl[j] = tot ++; else ans += ci[tmp][ini[j]][j];
for (int j = ; j <= nn; ++ j)
for (int k = ; k <= nn; ++ k)
ci[!tmp][j][k] = INF;
for (int j = ; j <= nn; ++ j)
for (int k = ; k <= nn; ++ k)
{
if (!inc[j])
{
if (!inc[k])
ci[!tmp][inl[j]][inl[k]] = min(ci[!tmp][inl[j]][inl[k]], ci[tmp][j][k]);
else
ci[!tmp][inl[j]][tot] = min(ci[!tmp][inl[j]][tot], ci[tmp][j][k] - ci[tmp][ini[k]][k]);
}
else if (!inc[k])
ci[!tmp][tot][inl[k]] = min(ci[!tmp][tot][inl[k]], ci[tmp][j][k]);
}
nn = tot;
break;
}
}
if (!wh)
for (int i = ; i <= nn; ++ i) ans += ci[tmp][ini[i]][i];
else tmp ^= ;
}
printf("%.2lf", ans);
}

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