poj2456

Aggressive cows

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 24979		Accepted: 11594

Description

Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a straight line at positions x1,...,xN (0 <= xi <= 1,000,000,000).

His C (2 <= C <= N) cows don't like this barn layout and become aggressive towards each other once put into a stall. To prevent the cows from hurting each other, FJ want to assign the cows to the stalls, such that the minimum distance between any two of them is as large as possible. What is the largest minimum distance?

Input

* Line 1: Two space-separated integers: N and C

* Lines 2..N+1: Line i+1 contains an integer stall location, xi

Output

* Line 1: One integer: the largest minimum distance

Sample Input

Sample Output

Hint

OUTPUT DETAILS:

FJ can put his 3 cows in the stalls at positions 1, 4 and 8, resulting in a minimum distance of 3.

Huge input data,scanf is recommended.

Source

USACO 2005 February Gold

一句话题意：

有n个牛栏，k头牛。将这k头牛放入牛栏中，如何保证牛与牛之间最小的距离最大。

解析：

明显的是二分算法。

L=0；R= 最大值

#include<iostream>

#include<cstdio>

#include<algorithm>

using namespace std;

const int maxn=;

int n,k;

int a[maxn];

int check(int x){

    int cnt=;

    int y=a[];

    for(int i=;i<=n;i++)

        if(a[i]-y>=x){

            cnt++;y=a[i];

            if(cnt>=k) return ;

        }

    return ;

}

int main(){

    cin>>n>>k;

    for(int i=;i<=n;i++){

        cin>>a[i];

    }

    sort(a+,a++n);

    int l=,r=a[n],mid;

    while (l<r){

        mid=(l+r+)/;

        if(check(mid)) l=mid;

        else r=mid-;

    }

    cout<<l<<endl;

    return ;

}

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poj2456

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