[LeetCode&Python] Problem 705. Design HashSet
2024-08-24 20:34:07
Design a HashSet without using any built-in hash table libraries.
To be specific, your design should include these functions:
add(value): Insert a value into the HashSet.contains(value): Return whether the value exists in the HashSet or not.remove(value): Remove a value in the HashSet. If the value does not exist in the HashSet, do nothing.
Example:
MyHashSet hashSet = new MyHashSet();
hashSet.add(1);
hashSet.add(2);
hashSet.contains(1); // returns true
hashSet.contains(3); // returns false (not found)
hashSet.add(2);
hashSet.contains(2); // returns true
hashSet.remove(2);
hashSet.contains(2); // returns false (already removed)
Note:
- All values will be in the range of
[0, 1000000]. - The number of operations will be in the range of
[1, 10000]. - Please do not use the built-in HashSet library.
class MyHashSet(object):
def __init__(self):
"""
Initialize your data structure here.
"""
self.hashSet=set()
def add(self, key):
"""
:type key: int
:rtype: void
"""
self.hashSet.add(key)
def remove(self, key):
"""
:type key: int
:rtype: void
"""
if key in self.hashSet:
self.hashSet.remove(key)
def contains(self, key):
"""
Returns true if this set contains the specified element
:type key: int
:rtype: bool
"""
if key in self.hashSet:
return True
else:
return False
# Your MyHashSet object will be instantiated and called as such:
# obj = MyHashSet()
# obj.add(key)
# obj.remove(key)
# param_3 = obj.contains(key)
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