poj 2262 筛法求素数（巧妙利用数组下标！）

Goldbach's Conjecture

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 41582		Accepted: 15923

Description

In 1742, Christian Goldbach, a German amateur mathematician, sent a letter to Leonhard Euler in which he made the following conjecture:

Every even number greater than 4 can be

written as the sum of two odd prime numbers.

For example:

8 = 3 + 5. Both 3 and 5 are odd prime numbers.

20 = 3 + 17 = 7 + 13.

42 = 5 + 37 = 11 + 31 = 13 + 29 = 19 + 23.

Today it is still unproven whether the conjecture is right. (Oh
wait, I have the proof of course, but it is too long to write it on the
margin of this page.)

Anyway, your task is now to verify Goldbach's conjecture for all even numbers less than a million.

Input

The input will contain one or more test cases.

Each test case consists of one even integer n with 6 <= n < 1000000.

Input will be terminated by a value of 0 for n.

Output

For
each test case, print one line of the form n = a + b, where a and b are
odd primes. Numbers and operators should be separated by exactly one
blank like in the sample output below. If there is more than one pair of
odd primes adding up to n, choose the pair where the difference b - a
is maximized. If there is no such pair, print a line saying "Goldbach's
conjecture is wrong."

Sample Input

Sample Output

8 = 3 + 5

20 = 3 + 17

42 = 5 + 37

Source

Ulm Local 1998

心得：自己写的筛法时间复杂度是O（n^2）,利用数组下标省去一个循环后变成了O(n);妙不可言！！！

#include <iostream>

#include<cstdio>

#include<cstring>

using namespace std;

#define N 1000000

int n,a[N];

bool pr[N];

void pdd()

{

    int i,j;

    for(i=;i<;i++) a[i]=;

    a[]=; a[]=;

    for(i=;i<;i++)

    {

        if(a[i]==)

        {

            for(j=i*;j<;j+=i) a[j]=;

        }

    }

}

int main()

{

    int num;

    int i,flag;

    pdd();

    while(scanf("%d",&num)!=EOF&&num!=)

    {

        for(flag=,i=;i<num;i++)

        {

            if(a[i]==&&a[num-i]==)

            {

                printf("%d = %d + %d\n",num,i,num-i);

                flag=;

                break;

            }

        }

        if(flag==)

            printf("Goldbach's conjecture is wrong.\n");

    }

    return ;

}

巴特西

poj 2262 筛法求素数（巧妙利用数组下标！）

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