将json格式转为url参数格式的方法(xjl456852整理修改)

测试页面:

<html>
  <head>
    <script type="text/javascript" src="jquery-1.11.3.min.js"></script>
  </head>
 <body>
    <div id="div1">
      <button onclick="test1()">
        t1
      </button>

      <button onclick="test2()">
        t2
      </button>
      <button onclick="test3()">
        t3
      </button>
   </div>
  </body>
  <script type="text/javascript">

      var parseParam = function(param, key) {
          var paramStr = "";
          if (typeof param == 'string' || typeof param == 'number' || typeof param == 'boolean') {
              paramStr += "&" + key + "=" + encodeURIComponent(param);
          } else {
              $.each(param, function(i,tmp) {
                  var k = key == null ? i : key + (param instanceof Array ? "[" + i + "]" : "." + i);
                  paramStr += '&' + parseParam(tmp, k);
              });
          }
          return paramStr.substr(1);
      };


      function test1() {
        console.log(parseParam({"a":"12","b":123}));
      }

      function test2() {
        console.log(parseParam({a:"12",b:123},"user"));
      }

      function test3() {
        console.log(parseParam([1,2,3],"hh"));
      }
      
  </script>
</html>

测试结果:

a=12&b=123

user.a=12&user.b=123

hh[0]=1&hh[1]=2&hh[2]=3

null

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将json格式转为url参数格式的方法(xjl456852整理修改)

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