【Selenium】跳转问题

/**
* rewrite the get method, adding user defined log
* 地址跳转方法，使用WebDriver原生get方法，加入失败重试的次数定义。
*
* @param url the url you want to <a target=_blank id="2_nwl" href="http://cpro.baidu.com/cpro/ui/uijs.php?adclass=0&app_id=0&c=news&cf=1001&ch=0&di=128&fv=11&is_app=0&jk=69829344341ee6cd&k=open&k0=open&kdi0=0&luki=2&n=10&p=baidu&q=v77y4_cpr&rb=0&rs=1&seller_id=1&sid=cde61e3444938269&ssp2=1&stid=0&t=tpclicked3_hc&td=2102575&tu=u2102575&u=http%3A%2F%2Fwww%2Eylzx8%2Ecn%2Fzonghe%2Fopen%2Dsource%2F247951%2Ehtml&urlid=0" target="_blank" mpid="2" style="color: rgb(1, 70, 108); text-decoration: none;">open</a>.
* @param actionCount retry times when load timeout occuers.
* @throws RuntimeException
*/
protected void get(String url, int actionCount) {
boolean inited = false;
int index = 0, timeout = 10;
while (!inited && index < actionCount){
timeout = (index == actionCount - 1) ? maxLoadTime : 10;//最后一次跳转使用最大的默认超时时间
inited = navigateAndLoad(url, timeout);
index ++;
}
if (!inited && index == actionCount){//最终跳转失败则抛出运行时异常，退出运行
throw new RuntimeException("can not get the url [" + url + "] after retry " + actionCount + "times!");
}
}
/**
* rewrite the get method, adding user defined log
* 地址跳转方法，使用WebDriver原生get方法，默认加载超重试【1】次。
*
* @param url the url you want to open.
* @throws RuntimeException
*/
protected void get(String url) {
get(url, 2);
}
/**
* judge if the url has navigate and page load completed.
* 跳转到指定的URL并且返回是否跳转完整的结果。
*
* @param url the url you want to open.
* @param timeout the timeout for page load in seconds.
* @return if page load completed.
*/
private boolean navigateAndLoad(String url, int timeout){
try {
driver.manage().timeouts().pageLoadTimeout(timeout, TimeUnit.SECONDS);
driver.get(url);
return true;//跳转并且加载页面成功在返回true
} catch (TimeoutException e) {
return false;//超时的情况下返回false
} catch (Exception e) {
failValidation();//共用的异常处理方法
LOG.error(e);//记录错误日志
throw new RuntimeException(e);//抛出运行时异常，退出运行
}finally{
driver.manage().timeouts().pageLoadTimeout(maxLoadTime, TimeUnit.SECONDS);
}
}

巴特西

【Selenium】跳转问题

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