#include<cstdio>

#include<cstring>

#include<cmath>

#include<iostream>

#include<algorithm>

#include<queue>

using namespace std;

const double eps = 1e-;

const double PI = acos(-1.0);

const double INF = 1000000000000000.000;

struct Point{

    double x,y;

    Point(double x=, double y=) : x(x),y(y){ }    //构造函数

};

typedef Point Vector;

struct Circle{

     Point C;

     double r;

     Circle(Point C=Point(,),double r=0.0): C(C),r(r) {}

     Point getpoint(double ang){   //可以用来求圆上与x正半轴成ang度的点的坐标。

        return Point(C.x +cos(ang)*r,C.y + sin(ang)*r);

     }

};

Vector operator + (Vector A , Vector B){return Vector(A.x+B.x,A.y+B.y);}

Vector operator - (Vector A , Vector B){return Vector(A.x-B.x,A.y-B.y);}

Vector operator * (double p,Vector A){return Vector(A.x*p,A.y*p);}

Vector operator / (Vector A , double p){return Vector(A.x/p,A.y/p);}

bool operator < (const Point& a,const Point& b){

    return a.x < b.x ||( a.x == b.x && a.y < b.y);

}

int dcmp(double x){

    if(fabs(x) < eps) return ;

    else              return x <  ? - : ;

}

bool operator == (const Point& a, const Point& b){

    return dcmp(a.x - b.x) ==  && dcmp(a.y - b.y) == ;

}

///向量（x,y）的极角用atan2(y,x);

inline double Dot(Vector A, Vector B){ return A.x*B.x + A.y*B.y; }

inline double Length(Vector A)    { return sqrt(Dot(A,A)); }

inline double Angle(Vector A, Vector B)  { return acos(Dot(A,B) / Length(A) / Length(B)); }

double Cross(Vector A, Vector B)  { return A.x*B.y - A.y * B.x; }

Vector vecunit(Vector v){ return v / Length(v);} //单位向量

/*************************************分 割 线*****************************************/

const int maxn = ;

Circle cir[maxn];

int N;

double R,r;

int main()

{

    //freopen("E:\\acm\\input.txt","r",stdin);

    cin>>N;

    for(int i=;i<=N;i++){

       scanf("%lf %lf",&cir[i].C.x,&cir[i].C.y);

    }

    scanf("%lf %lf",&R,&r);

    if(dcmp(R-r) < ){

        printf("0\n");

        return ;

    }

    Circle NewC;

    NewC.r = R;

    for(int i=;i<=N;i++){

        cir[i].r = r;

    }

    double ave = *PI / ;

    int ans = ;

    for(int i=;i<=N;i++){

        for(double ang=;ang<=*PI;ang+=ave){

            int temp = ;

            Point P = cir[i].getpoint(ang);   //在圆上取点。

            NewC.C = P + R * (cir[i].C-P)/Length(cir[i].C-P);

            for(int j=;j<=N;j++){

                if(i == j) continue;

                if(dcmp(fabs(NewC.r-cir[j].r) - Length(NewC.C - cir[j].C)) >= ) {

                     temp++;

                }

            }

            ans = max(ans,temp);

        }

    }

    printf("%d\n",ans);

}