方法一

from datetime import datetime

from pytz import timezone

cst_tz = timezone('Asia/Shanghai')

utc_tz = timezone('UTC')

pst_tz = timezone('America/Los_Angeles')

day = datetime.strptime('2020-12-11 20:00:00', '%Y-%m-%d %H:%M:%S')

aa = day.astimezone(tz=cst_tz).strftime('%Y-%m-%d %H:%M:%S')

bb = day.astimezone(tz=pst_tz).strftime('%Y-%m-%d %H:%M:%S')

cc = day.astimezone(tz=utc_tz).strftime('%Y-%m-%d %H:%M:%S')

print('北京时间:', aa)

print('太平洋时间:', bb)

print('utc时间:', cc)

方法二

import calendar

from datetime import datetime, date, timedelta

MARKETPLACES = {'US': 'NA',

                'CA': 'NA',

                'JP': 'FE',

                'AU': 'FE',

                'UK': 'EU',

                'FR': 'EU',

                'IT': 'EU',

                'ES': 'EU',

                'DE': 'EU',

                'AE': 'EU',

                }

def get_weekday(datetime_obj, week_day="monday"):

    """

    获取指定时间的当周的星期x

    :param datetime_obj: 时间

    :param week_day: 指定的星期x

    :return:

    """

    d = dict(zip(("monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday"),

                 range(7)))  # datetime 模块中，星期一到星期天对应数字 0 到 6

    delta_hour = timedelta(days=1)  # 改变幅度为 1 天

    while datetime_obj.weekday() != d.get(week_day):

        if datetime_obj.weekday() > d.get(week_day):

            datetime_obj -= delta_hour

        elif datetime_obj.weekday() < d.get(week_day):

            datetime_obj += delta_hour

        else:

            pass

    return datetime_obj

def get_month_weekday(year, month, n=1, w="sunday", h=0):

    """

    获取 year 年，month 月的的第n个星期w和倒数第n个星期w的日期

    :param year: 指定年份，

    :param month: 指定月份

    :param n: n个或者倒是n个

    :param w: 指定的星期w

    :param h: 指定的小时

    :return:

    """

    # 获取第一和最后一天

    d = dict(zip(("monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday"),

                 range(7)))  # datetime 模块中，星期一到星期天对应数字 0 到 6

    weekday, count_day = calendar.monthrange(year=year, month=month)  # 返回指定月份1号的星期几，和本月的总天数

    first_day = datetime(year=year, month=month, day=1, hour=h)  # <type 'datetime.datetime'>

    last_day = datetime(year=year, month=month, day=count_day, hour=h)

    if n > 0:

        n = abs(n)

        if first_day.weekday() > d.get(w):  # 说明本周的星期w在上个月

            datetime_obj = first_day + timedelta(weeks=1)

        else:

            datetime_obj = first_day

        datetime_obj += timedelta(weeks=n - 1)

        weekday_day = get_weekday(datetime_obj=datetime_obj, week_day=w)

    else:

        n = abs(n)

        if last_day.weekday() < d.get(w):  # 说明本周的星期w在下一个月

            datetime_obj = last_day - timedelta(weeks=1)

        else:

            datetime_obj = last_day

        datetime_obj -= timedelta(weeks=n - 1)

        weekday_day = get_weekday(datetime_obj=datetime_obj, week_day=w)

    return weekday_day

def is_dst(dt, region):

    """

    "UK","DE","FR","ES","IT" 夏令时 取3月份的最后一个周日凌晨两点和10月份的最后一个星期天的凌晨1点

    "US","AU","CA","MX" 夏令时 取3月份的第二个周日凌晨两点和10月份的第一个星期天的凌晨两点

    :param dt: utc时间

    :return:  True:夏令时，Fasle:冬令时

    """

    if not isinstance(dt, datetime):

        raise ValueError("dt需为dtatime类型")

    year = dt.year

    if region == ["UK", "DE", "FR", "ES", "IT"]:

        summer_start_month = 3

        summer_start_n = -1

        summer_start_w = "sunday"

        summer_start_h = 2

        summer_end_month = 10

        summer_end_n = -1

        summer_end_w = "sunday"

        summer_end_h = 1

    elif region == ["US", "AU", "CA", "MX"]:

        summer_start_month = 3

        summer_start_n = 2

        summer_start_w = "sunday"

        summer_start_h = 2

        summer_end_month = 10

        summer_end_n = 1

        summer_end_w = "sunday"

        summer_end_h = 2

    else:

        raise ValueError(f"不支持当前国家{region}")

    sum_start = get_month_weekday(year, summer_start_month, n=summer_start_n, w=summer_start_w, h=summer_start_h)

    sum_end = get_month_weekday(year, summer_end_month, n=summer_end_n, w=summer_end_w, h=summer_end_h)

    print(sum_start, sum_end)

    if sum_start <= dt <= sum_end:

        return True

    return False

def conversion_time(dt, region="US"):

    """

    :param dt:  utc时间

    :param region: 国家地区

    :return: 当地时间

    """

    if region in ["US", "AU", "CA", "MX"]:

        dt = dt + timedelta(hours=-7) if is_dst(dt, region) else dt + timedelta(hours=-8)

    elif region == "UK":

        dt = dt + timedelta(hours=1) if is_dst(dt, region) else dt

    elif region in ["DE", "FR", "ES", "IT"]:

        dt = dt + timedelta(hours=2) if is_dst(dt, region) else dt + timedelta(hours=1)

    elif region == "JP":

        dt = dt + timedelta(hours=9)

    elif region == "IN":

        dt = dt + timedelta(hours=5)

    elif region == "SG":

        dt = dt + timedelta(hours=8)

    else:

        raise ValueError(f"不支持当前国家{region}")

    return dt

if __name__ == '__main__':

    # t = datetime(year=2020,month=11,day=19,hour=16)

    t = datetime.utcnow()

    print(conversion_time(t, region="JP"))

巴特西

utc时间转换为太平洋时间

方法一

方法二

最新文章

热门文章