time limit per test2 seconds

memory limit per test256 megabytes

inputstandard input

outputstandard output

Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.

In total, n students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to n. Let’s denote the rating of i-th student as ai. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.

He thinks that each student will take place equal to . In particular, if student A has rating strictly lower then student B, A will get the strictly better position than B, and if two students have equal ratings, they will share the same position.

GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.

Input

The first line contains integer n (1 ≤ n ≤ 2000), number of GukiZ’s students.

The second line contains n numbers a1, a2, … an (1 ≤ ai ≤ 2000) where ai is the rating of i-th student (1 ≤ i ≤ n).

Output

In a single line, print the position after the end of the contest for each of n students in the same order as they appear in the input.

Examples

input

3

1 3 3

output

3 1 1

input

1

1

output

1

input

5

3 5 3 4 5

output

4 1 4 3 1

Note

In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.

In the second sample, first student is the only one on the contest.

In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position.

【题目链接】:http://codeforces.com/contest/551/problem/A

【题解】



模拟

模拟它的要求排序就好了.

用结构体比较方便。



【完整代码】

#include <bits/stdc++.h>

using namespace std;

#define lson l,m,rt<<1

#define rson m+1,r,rt<<1|1

#define LL long long

#define rep1(i,a,b) for (int i = a;i <= b;i++)

#define rep2(i,a,b) for (int i = a;i >= b;i--)

#define mp make_pair

#define pb push_back

#define fi first

#define se second

#define rei(x) scanf("%d",&x)

#define rel(x) scanf("%I64d",&x)

typedef pair<int,int> pii;

typedef pair<LL,LL> pll;

const int MAXN = 2000+100;

const int dx[9] = {0,1,-1,0,0,-1,-1,1,1};

const int dy[9] = {0,0,0,-1,1,-1,1,-1,1};

const double pi = acos(-1.0);

struct abc

{

    int x,pos;

};

int n;

abc a[MAXN];

int ans[MAXN];

bool cmp(abc a,abc b)

{

    return a.x < b.x;

}

int main()

{

    //freopen("F:\\rush.txt","r",stdin);

    scanf("%d",&n);

    rep1(i,1,n)

        rei(a[i].x),a[i].pos = i;

    sort(a+1,a+1+n,cmp);

    rep1(i,1,n)

    {

        int l = i,r = i;

        while (r+1<=n && a[r+1].x == a[l].x)

            r++;

        int temp = n-r+1;

        rep1(j,l,r)

            ans[a[j].pos] = temp;

    }

    rep1(i,1,n)

        {

            printf("%d",ans[i]);

            if (i==n)

                puts("");

            else

                putchar(' ');

        }

    return 0;

}