(Py练习)判断能被几个9整除

# 输入一个奇数，判断最少几个9除以该数的结果为整数

# 999999 / 13 = 76923

if __name__ == '__main__':

    zi = int(input("输入一个奇数：\n"))

    n1 = 1

    c9 = 1

    m9 = 9

    sum = 9

    while n1 != 0:

        if sum % zi == 0:

            n1 = 0

        else:

            m9 *= 10

            sum += m9

            c9 += 1

    print("%d个9可以被%d整除：%d" % (c9, zi, sum))

    r = sum / zi

    print('%d / %d = %d' % (sum, zi, r))

巴特西

(Py练习)判断能被几个9整除

最新文章

热门文章