Double NaN

import java.math.BigDecimal;

import java.math.RoundingMode;

public class Test {

    public static void main(String f[]) {

        Double dto = 1.0/0;

        Double vo = dto + 2.0;

        Double po = getPresicionScale(vo);

    }

    static Double getPresicionScale(Double actualValue)

    {

        Double value=0.0;

        if(actualValue!=null)

        {

            return  BigDecimal.valueOf(actualValue).setScale( 5, RoundingMode.DOWN).doubleValue();

        }

        return value;

    }

}

Exception in thread "main" java.lang.NumberFormatException: Character I is neither a decimal digit number, decimal point, nor "e" notation exponential mark.
at java.base/java.math.BigDecimal.<init>(BigDecimal.java:518)
at java.base/java.math.BigDecimal.<init>(BigDecimal.java:401)
at java.base/java.math.BigDecimal.<init>(BigDecimal.java:834)
at java.base/java.math.BigDecimal.valueOf(BigDecimal.java:1304)
at com.jds.test.httpproxy.miniserver.Test.getPresicionScale(Test.java:19)
at com.jds.test.httpproxy.miniserver.Test.main(Test.java:11)

報錯的堆棧奇特

public static BigDecimal valueOf(double val) {
    // Reminder: a zero double returns '0.0', so we cannot fastpath
    // to use the constant ZERO.  This might be important enough to
    // justify a factory approach, a cache, or a few private
    // constants, later.
    return new BigDecimal(Double.toString(val));
}

1/0 沒報錯

1/0+2 沒報錯

Double -> double 沒報錯

在BigDeciaml構造報錯

Double.isNaN isInfite 判斷

巴特西

Double NaN

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