Fractions in octal (base 8) notation can be expressed exactly in decimal notation. For example, 0.75 in octal is 0.953125 (7/8 + 5/64) in decimal. All octal numbers of n digits to the right of the octal point can be expressed in no more than 3n decimal digits to the right of the decimal point.

Write a program to convert octal numerals between 0 and 1, inclusive, into equivalent decimal numerals.

The
input to your program will consist of octal numbers, one per line, to
be converted. Each input number has the form 0.d1d2d3 ... dk, where the
di are octal digits (0..7). There is no limit on k.

Your output will consist of a sequence of lines of the form

0.d1d2d3 ... dk [8] = 0.D1D2D3 ... Dm [10]
where
the left side is the input (in octal), and the right hand side the
decimal (base 10) equivalent. There must be no trailing zeros, i.e. Dm
is not equal to 0.

#include <stdio.h>

#include <string.h>

#define MAXN 10000

char d[MAXN];

int D[MAXN];

int main()

{

    int cnt;//表示当前数组存放的位置

    int next;

    int current;

    while(gets(d)!=NULL){

        int len=strlen(d);

        int Dlen=;

        memset(D,,sizeof(D));

        for(int i=len-; i>=; i--){

            cnt=;

            int num=d[i]-'';

            next=num;

            while(next!= || cnt<Dlen){

                current=next*+D[cnt];

                D[cnt++]=current/;

                next=current%;

            }

            Dlen=cnt;

        }

        printf("%s [8] = 0.",d);

        for(int i=; i<cnt; i++){

            printf("%d",D[i]);

        }

        printf(" [10]\n");

    }

    return ;

}