Move Zeroes

题目描述：

Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements.

For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].

Note:
You must do this in-place without making a copy of the array.
Minimize the total number of operations.
Credits:
Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.

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思路：

说实话。刚看到有点头大，后面尝试写，思路是遍历每一个元素，如果是0，就把后面的元素往前移动一个，然后把零移到后面。

注意：在循环的时候，不要急着对循环变量加1，先判断移动后，是不是0.如果是零，接着移动，不加1.还有每次移动，都把后面就加一个 零，设置一个变量count技术，后面循环n = n - count

代码：

public class Solution {
    public void moveZeroes(int[] nums) {
        int n = nums.length;
        //用来后面减去移动次数的计数
        int num = n;
        int i = 0;
        while(i < num){
            if(nums[i] == 0){
                int last = nums[i];
                for(int a = i;a < n-1;a++){
                    nums[a] = nums[a+1];
                }
                nums[n-1] = last;
            }
            if(nums[i] != 0){
            //如果不是零，才往后加1
                i = i+1;
            }else{
            //减去移动次数，与因为后面都是零
                num = num-1;
            }
        }
    }
}