POJ C++程序设计 编程题#1 编程作业—文件操作与模板
2024-10-19 04:28:29
编程题#1
来源: POJ (Coursera声明:在POJ上完成的习题将不会计入Coursera的最后成绩。)
注意: 总时间限制: 1000ms 内存限制: 65536kB
描述
实现一个三维数组模版CArray3D,可以用来生成元素为任意类型变量的三维数组,使得下面程序输出结果是:
0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,
注意,只能写一个类模版,不能写多个。
#include <iostream>
using namespace std;
// 在此处补充你的代码
int main()
{
CArray3D<int> a(3,4,5);
int No = 0;
for( int i = 0; i < 3; ++ i )
for( int j = 0; j < 4; ++j )
for( int k = 0; k < 5; ++k )
a[i][j][k] = No ++;
for( int i = 0; i < 3; ++ i )
for( int j = 0; j < 4; ++j )
for( int k = 0; k < 5; ++k )
cout << a[i][j][k] << ",";
return 0;
}
输入
无
输出
0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,
样例输入
无
样例输出
0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,
提示
提示:类里面可以定义类,类模版里面也可以定义类模版。例如:
class A
{
class B { };
}; template
class S
{
T x;
class K {
T a;
};
};
#include <iostream>
using namespace std;
// 在此处补充你的代码
template <class T>
class CArray3D {
public:
template <class T1>
class CArray2D {
private:
T1 *a;
int i,j;
public:
CArray2D() {a = NULL;}
CArray2D(int a1, int a2):i(a1),j(a2) {
a = new T1[i*j];
}
~CArray2D() {
if (a != NULL) delete []a;
}
T1 *operator[](int a1) {
return a + a1*j;
}
};
CArray3D() {array2D = NULL;}
CArray3D(int a1, int a2, int a3) {
array2D = new CArray2D<T>*[a1];
for (int m = ; m < a1; ++m) {
array2D[m] = new CArray2D<T>(a2, a3);
}
}
CArray2D<T> &operator[](int i) {
return *array2D[i];
}
~CArray3D() {
if (array2D != NULL) delete []array2D;
}
private:
CArray2D<T> **array2D;
};
int main()
{
CArray3D<int> a(,,);
int No = ;
for( int i = ; i < ; ++ i )
for( int j = ; j < ; ++j )
for( int k = ; k < ; ++k )
a[i][j][k] = No ++;
for( int i = ; i < ; ++ i )
for( int j = ; j < ; ++j )
for( int k = ; k < ; ++k )
cout << a[i][j][k] << ",";
return ;
}
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