//十六进制转二进制，二进制转八进制 

 #include <iostream>

 #include <map>

 using namespace std;

 int main() {

     string s;            //输入的十六进制

     string binaryNum;    //二进制数

     int n;

     cin >> n;

     string str[] = {"", "", "", "",

                       "", "", "", "",

                       "", "", "", "",

                       "", "", "", ""};

     map<string, string> m;

     m[""] = ""; m[""] = ""; m[""] = ""; m[""] = "";

     m[""] = ""; m[""] = ""; m[""] = ""; m[""] = "";

     for (int i = ; i < n; i++)

     {

         cin >> s;

         int len_s = s.length();

         for(int j = ; j < len_s; j++)

         {

             if(s[j] > '')

             {

                 binaryNum += str[s[j] - 'A' + ];

             }

             else

             {

                 binaryNum += str[s[j] - ''];

             }

         }

         int len_b = binaryNum.length();            //二进制数的长度

         if(len_b %  == )                         //将二进制的长度转为3的倍数

         {

             binaryNum = "" + binaryNum;

         }

         else if(len_b %  == )

         {

             binaryNum = "" + binaryNum;

         }

         int flag = ;        //前导为0标志

         string temp;        //获取三位二进制数，将其转为八进制

         string octalNum;    //八进制数

         for(int j = ; j < len_b; j += )

         {

             temp = binaryNum.substr(j, );

             octalNum = m[temp];

             if(j ==  && octalNum == "")    //如果取出的二进制数前三位为0，则重新取接下来的3位二进制数

             {

                 flag = ;

                 continue;

             }

             if(flag ==  && j ==  && octalNum == "") //如果接下来的二进制还为0，则继续取（后边取的肯定不是0）

             {

                 continue;

             }

             cout << octalNum;

         }

         cout << endl;

         binaryNum = "";

     }

     return ;

 }