[LeetCode] 248. Strobogrammatic Number III 对称数之三
A strobogrammatic number is a number that looks the same when rotated 180 degrees (looked at upside down).
Write a function to count the total strobogrammatic numbers that exist in the range of low <= num <= high.
Example:
Input: low = "50", high = "100"
Output: 3
Explanation: 69, 88, and 96 are three strobogrammatic numbers.
Note:
Because the range might be a large number, the lowand high numbers are represented as string.
这道题是之前那两道 Strobogrammatic Number II 和 Strobogrammatic Number 的拓展，又增加了难度，让找给定范围内的对称数的个数，我们当然不能一个一个的判断是不是对称数，也不能直接每个长度调用第二道中的方法，保存所有的对称数，然后再统计个数，这样 OJ 会提示内存超过允许的范围，所以这里的解法是基于第二道的基础上，不保存所有的结果，而是在递归中直接计数，根据之前的分析，需要初始化 n=0 和 n=1 的情况，然后在其基础上进行递归，递归的长度 len 从 low 到 high 之间遍历，然后看当前单词长度有没有达到 len，如果达到了，首先要去掉开头是0的多位数，然后去掉长度和 low 相同但小于 low 的数，和长度和 high 相同但大于 high 的数，然后结果自增1，然后分别给当前单词左右加上那五对对称数，继续递归调用，参见代码如下：
解法一：
class Solution {
public:
int strobogrammaticInRange(string low, string high) {
int res = ;
for (int i = low.size(); i <= high.size(); ++i) {
find(low, high, "", i, res);
find(low, high, "", i, res);
find(low, high, "", i, res);
find(low, high, "", i, res);
}
return res;
}
void find(string low, string high, string path, int len, int &res) {
if (path.size() >= len) {
if (path.size() != len || (len != && path[] == '')) return;
if ((len == low.size() && path.compare(low) < ) || (len == high.size() && path.compare(high) > )) {
return;
}
++res;
}
find(low, high, "" + path + "", len, res);
find(low, high, "" + path + "", len, res);
find(low, high, "" + path + "", len, res);
find(low, high, "" + path + "", len, res);
find(low, high, "" + path + "", len, res);
}
};
上述代码可以稍微优化一下，得到如下的代码：
解法二：
class Solution {
public:
int strobogrammaticInRange(string low, string high) {
int res = ;
find(low, high, "", res);
find(low, high, "", res);
find(low, high, "", res);
find(low, high, "", res);
return res;
}
void find(string low, string high, string w, int &res) {
if (w.size() >= low.size() && w.size() <= high.size()) {
if (w.size() == high.size() && w.compare(high) > ) {
return;
}
if (!(w.size() > && w[] == '') && !(w.size() == low.size() && w.compare(low) < )) {
++res;
}
}
if (w.size() + > high.size()) return;
find(low, high, "" + w + "", res);
find(low, high, "" + w + "", res);
find(low, high, "" + w + "", res);
find(low, high, "" + w + "", res);
find(low, high, "" + w + "", res);
}
};
Github 同步地址：
https://github.com/grandyang/leetcode/issues/248
类似题目：
参考资料：
https://leetcode.com/problems/strobogrammatic-number-iii/
LeetCode All in One 题目讲解汇总(持续更新中...)
最新文章
- linux常用查看硬件设备信息命令
- JAVA 线程中的异常捕获
- JMeter基础之--元件的作用域与执行顺序
- python 语料处理（从文件夹中读取文件夹中文件，分词，去停用词，去单个字）
- mybatis 相关总结
- cloudera安装报错 socket.gaierror: [Errno -2] Name or service not known
- JAVA toString方法
- /usr/lib/libstdc++.so.6: version `GLIBCXX_3.4.15' not found错误的解决
- Radar Installation（POJ 1328 区间贪心）
- c语言，数据类型转换
- Math 对象 识记
- Django REST framework 中 3 种类视图的对比
- 嘿嘿嘿，开始自学mysql
- mysql一列相同另一列相加
- 获取子元素节点(children,childNodes)
- java 反射原理写了一个赋值和取值通用类
- Java 常用对象-Date类和Calender类
- Win窗口坐标二维坐标与OpenGl的世界坐标系的之间的相互转换
- Oil Skimming---hdu4185（最大匹配）
- 使用.sig签名验证文件