class solution:

    def getChar(self,s):

        setS = set(s)

        dict = {}

        for i in setS:

            dict[i] = s.count(i)     #该方法返回子字符串在字符串中出现的次数。

        for index,value in enumerate(s):

            print('j'+str(index)+' , k'+str(value))

            if dict.get(value) == 1:

                return index

        return -1

    def getChar2(self,s):

        return min([s.find(c) for c in 'abcdefghijklmnopqrstuvwxyz' if s.count(c)==1] or [-1])

if __name__ == "__main__":

    solution = solution()

    index = solution.getChar('leetcode')

    index2 = solution.getChar('loveleetcode')

    print(index)

    print(index2)

    print(solution.getChar2('leetcode'))

    print(solution.getChar2('loveleetcode'))