2、python--第二天练习题



#1.有如下值集合 [11,22,33,44,55,66,77,88,99,90...]，将所有大于 66 的值保存至字典的第一个key中，将小于 66 的值保存至第二个key的值中。

#即： {'k1': 大于66的所有值, 'k2': 小于66的所有值}

b = [11, 22, 33, 44, 55, 66, 77, 88, 99, 90]

a = {'k1':[],'k2':[]}

for i in b:

    if i <= 66:

        a['k1'].append(i)

    else:

        a['k2'].append(i)

print(a)

#2.查找列表中元素，移除每个元素的空格，并查找以 a或A开头 并且以 c 结尾的所有元素。

li = ["alec", " aric", "Alex", "Tony", "rain"]

tu = ("alec", " aric", "Alex", "Tony", "rain")

dic = {'k1': "alex", 'k2': ' aric',  "k3": "Alex", "k4": "Tony"}

for i in li:

    if (i.strip().startswith('a') or i.strip().startswith('A')) and i.strip().endswith('c'):

        print(i.strip())

for i in dic.values():

    if (i.strip().startswith('a') or i.strip().startswith('A')) and i.strip().endswith('c'):

        print(i.strip())

#3.输出商品列表，用户输入序号，显示用户选中的商品

li = ["手机", "电脑", '鼠标垫', '游艇']

for k,v in enumerate(li):

    print(str(k) +' : ' +v)

a = int(input("您选择的商品序号序号："))

if a > 0 and a < len(li):

	print('您选择的商品是：' + li[a])

else:

    print('商品不存在')

#4.购物车

#功能要求：要求用户输入总资产，例如：2000，显示商品列表，让用户根据序号选择商品，加入购物车，购买，如果商品总额大于总资产，提示账户余额不足，否则，购买成功。

#附加：可充值、某商品移除购物车

goods = [

    {"name": "电脑", "price": 1999},

    {"name": "鼠标", "price": 10},

    {"name": "游艇", "price": 20},

    {"name": "美女", "price": 998},

]

Shopping = []

money = 0

sum_all= 0

credit = int(input('您现在有:' + '0 元，请输入您充值的金额：'))

print('您本次预存：' + str(credit) + '元')

while True:

    for o, p in enumerate(goods):

        print('商品序号' + str(o), ':' + p['name'] + '; 价格:' + str(p['price']))

    a = input("请输入您选择的商品序号[输入q结算]：")

    if a.isdigit():

        if int(a) > o:

            print('商品不存在,请重新选择！')

        elif int(a) <= o:

            sum_all += goods[int(a)]['price']

            if credit >= sum_all:

                Shopping.append(goods[int(a)]['name'])

                money += goods[int(a)]['price']

                print('商品:'+ goods[int(a)]['name'] +';已加入购物车，购物车清单：[' + ' '.join(Shopping) + '] 预计消费' + str(sum_all) +'元')

            else:

                print("余额不足！购物车清单:[" + ' '.join(Shopping)+ "], 您的预存金额为：" + str(credit) + '元，您预计消费为：' + str(sum_all) +'元；差' + str(sum_all-credit) +'元')

                sum_all -= goods[int(a)]['price']

                c = input("是否继续充值(y是/n否)：")

                if c == 'y':

                    d = input("请输入充值金额：")

                    credit += int(d)

                    print("您充值了%s元"%d)

                elif c == 'n':

                    continue

                else:

                    print("输入错误")

        else:

            print('输入错误！请输入您选择的商品序号[输入q结算]：')

    if a.lower() == 'q':

        print('您的购物清单如下:[%s];共消费:%s元；剩余：%s元' % (' '.join(Shopping), money, (credit - money)))

        break

#5、用户交互，显示省市县三级联动的选择

dic = {

    "河北": {

        "石家庄": ["鹿泉", "藁城", "元氏"],

        "邯郸": ["永年", "涉县", "磁县"],

    },

    "河南": {

        "郑州":["中原","金水","中牟","二七"],

        "商丘":["虞城","夏邑","宁陵","永城"],

    },

    "山西": {

        "太原":["小店","古交","迎泽"],

        "大同":["平城","云冈","广灵"],

    }

}

while True:

    for i in dic:

        print(i)

    sheng = input("请输入省份:")

    for k in dic[sheng]:

        print(k)

    shi = input("请输入市,退出按q:")

    if shi.lower() == 'q':

        break

    for j in dic[sheng][shi]:

        print(j)

    print('已经到底了，请继续选择省份！')
巴特西

2、python--第二天练习题

最新文章

热门文章
