php实现‘浏览记录’按日期分组
2024-10-11 15:38:45
出题:现有测试数据如下,要求实现如下图中的效果:
array(4) {
[0] => array(6) {
["visit_id"] => int(127)
["goods_id"] => int(16)
["visittime"] => int(1494399935)
["goods_name"] => string(53) "OPPO R9s 全网通4G+64G 双卡双待手机 玫瑰金"
["shop_price"] => string(6) "500.00"
}
[1] => array(6) {
["visit_id"] => int(124)
["goods_id"] => int(13)
["visittime"] => int(1494399921)
["goods_name"] => string(76) "SIEMENS/西门子 KA92NV09TI双开门家用对开门电冰箱变频旗舰款"
["shop_price"] => string(7) "4000.00"
}
[2] => array(6) {
["visit_id"] => int(123)
["goods_id"] => int(27)
["visittime"] => int(1494399903)
["goods_name"] => string(85) "爱他美白金版Aptamil 幼儿配方奶粉3段(12-36个月适用)900g(欧洲进口)"
["shop_price"] => string(6) "329.00"
}
[3] => array(6) {
["visit_id"] => int(120)
["goods_id"] => int(26)
["visittime"] => int(1494224263)
["goods_name"] => string(21) "欢乐谷免票一张"
["shop_price"] => string(5) "50.00"
}
}
还没实现之前我想这个代码不知道要O(n)
呢还是更高的复杂度才能实现,细想一下,其实php的数组底层就是哈希实现的,如何简单利用这个特性使复杂度降到O(1)
呢?
show me the code:
/* 浏览记录按日期分组 */
function groupVisit($visit)
{
$curyear = date('Y');
$visit_list = [];
foreach ($visit as $v) {
if ($curyear == date('Y', $v['visittime'])) {
$date = date('m月d日', $v['visittime']);
} else {
$date = date('Y年m月d日', $v['visittime']);
}
$visit_list[$date][] = $v;
}
return $visit_list;
}
说明:入参 $visit
就是上面一开始的测试数据,函数中还对用户体验做了一些优化,比如,你的浏览记录中总是显示出今年的年份,是不是感觉有点冗余,所以如果是本年份的话,年份就要隐藏起来,其他年份还是照样显示出来。不然代码会更加简洁,还是忍不住打出来,如下:
/* 简化版的函数 */
function groupVisit($visit)
{
$visit_list = [];
foreach ($visit as $v) {
$visit_list[date('Y年m月d日', $v['visittime'])][] = $v;
}
return $visit_list;
}
好,上面的测试数据经过该函数之后,再把返回值打印出来,有:
array(2) {
["05月10日"] => array(3) {
[0] => array(6) {
["visit_id"] => int(127)
["goods_id"] => int(16)
["visittime"] => int(1494399935)
["goods_name"] => string(53) "OPPO R9s 全网通4G+64G 双卡双待手机 玫瑰金"
["shop_price"] => string(6) "500.00"
}
[1] => array(6) {
["visit_id"] => int(124)
["goods_id"] => int(13)
["visittime"] => int(1494399921)
["goods_name"] => string(76) "SIEMENS/西门子 KA92NV09TI双开门家用对开门电冰箱变频旗舰款"
["shop_price"] => string(7) "4000.00"
}
[2] => array(6) {
["visit_id"] => int(123)
["goods_id"] => int(27)
["visittime"] => int(1494399903)
["goods_name"] => string(85) "爱他美白金版Aptamil 幼儿配方奶粉3段(12-36个月适用)900g(欧洲进口)"
["shop_price"] => string(6) "329.00"
}
}
["05月08日"] => array(1) {
[0] => array(6) {
["visit_id"] => int(120)
["goods_id"] => int(26)
["visittime"] => int(1494224263)
["goods_name"] => string(21) "欢乐谷免票一张"
["shop_price"] => string(5) "50.00"
}
}
}
对的,这正是我想要的效果。
思考:java或C++等其他后台语言要怎么简洁地实现这个效果呢?用map库?python用dictionary?
-end-
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