openURL in APP Extension

var responder = self as UIResponder?

while (responder != nil){

    if responder!.respondsToSelector(Selector("openURL:")) == true{

        responder!.callSelector(Selector("openURL:"), object: url, delay: 0)

    }

    responder = responder!.nextResponder()

}

This will find a suitable responder to send the openURL to.

You need to add this extension that replaces the performSelector for swift and helps in the construction of the mechanism:

extension NSObject {

    func callSelector(selector: Selector, object: AnyObject?, delay: NSTimeInterval) {

        let delay = delay * Double(NSEC_PER_SEC)

        let time = dispatch_time(DISPATCH_TIME_NOW, Int64(delay))

        dispatch_after(time, dispatch_get_main_queue(), {

            NSThread.detachNewThreadSelector(selector, toTarget:self, withObject: object)

        })

    }

}

&& Try it in OC

UIResponder *responder = self;

while(responder){

    if ([responder respondsToSelector: @selector(OpenURL:)]){

        [responder performSelector: @selector(OpenURL:) withObject: [NSURL URLWithString:@"www.google.com" ]];

    }

    responder = [responder nextResponder];

}

or

 UIResponder* responder = self;

    while ((responder = [responder nextResponder]) != nil)

    {

        NSLog(@"responder = %@", responder);

        if([responder respondsToSelector:@selector(openURL:)] == YES)

        {

            [responder performSelector:@selector(openURL:) withObject:[NSURL URLWithString:urlString]];

        }

    }

转载请注明出处。

巴特西

openURL in APP Extension

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