'''

Project Euler 17: Number letter counts

If the numbers 1 to 5 are written out in words:

one, two, three, four, five,

then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.

If all the numbers from 1 to 1000 (one thousand) inclusive

were written out in words, how many letters would be used?

NOTE: Do not count spaces or hyphens.

For example, 342 (three hundred and forty-two) contains 23 letters

and 115 (one hundred and fifteen) contains 20 letters.

The use of "and" when writing out numbers is in compliance with British usage.

Answer: 21124

'''

n1 = ['', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine']

n2 = ['', 'eleven', 'twelve', 'thirteen','fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen']

n3 = ['', 'ten', 'twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety']

sum = ''  #所有数字的英文表达累加

for i in range(1, 1001):

    baiwei = i//100  #百位数

    shiwei = (i - baiwei*100)//10  #十位数

    gewei = i%10  #个位数

    eng = ''  #当前数字的英文写法

    if i == 1000:

        eng += 'onethousand'

    elif i%100 == 0:  #若为整百的

        eng = n1[baiwei] + 'hundred'

    elif i > 100:

        eng = eng + n1[baiwei] + 'hundredand'

        if shiwei == 1 and gewei != 0:

            eng += n2[gewei]

        else:

            eng = eng + n3[shiwei] + n1[gewei]

    elif i > 19:

        eng = eng + n3[shiwei] + n1[gewei]

    elif i > 10:

        eng += n2[gewei]

    elif i == 10:

        eng += 'ten'

    else:

        eng += n1[gewei]

    sum += eng  #累加各个数字的英文表达

print(len(sum))