四种语言刷算法之 组合总和 II
2024-10-21 03:20:10
1、C
void back(int* candidates, int candidatesSize, int target,int start,int *path,int *pathSize,int **result,int** returnColumnSizes,int *visited,int* returnSize,int *sum){
if(*sum == target){
result[*returnSize] = (int *)malloc(sizeof(int)*(*pathSize));
memcpy(result[*returnSize],path,sizeof(int)*(*pathSize));
(*returnColumnSizes)[*returnSize] = *pathSize;
(*returnSize)++;
return;
}
for(int i=start;i<candidatesSize; i++){
if((*sum)+candidates[i]>target){break;}
if(i>0&&candidates[i-1]==candidates[i]&&visited[i-1]==0){
continue;
}
path[*pathSize] = candidates[i];
(*pathSize)++;
(*sum) += candidates[i];
visited[i] = 1;
back(candidates,candidatesSize,target,i+1,path,pathSize,result,returnColumnSizes,visited,returnSize,sum);
visited[i] = 0;
(*sum) -= candidates[i];
(*pathSize)--;
}
}
void QuickSort1(int* a, int left, int right)
{
if (left >= right)
{
return;
}
int begin = left, end = right;
//三数取中
//int midIndex = GetThreeMid(a,begin,end);
//Swap(&a[begin],&a[midIndex]);
int pivot = begin;
int key = a[begin]; while (begin < end)
{
//右边找小的,如果不是小于key,继续
while (begin < end && a[end] >= key)
{
end--;
}
//找到比key小的,把它放在坑里,换新坑
a[pivot] = a[end];
pivot = end;
//左边找大的,如果不是大于key,继续
while (begin < end && a[begin] <= key)
{
begin++;
}
//找到比key大的,把它放在坑里,换新坑
a[pivot] = a[begin];
pivot = begin;
}
a[pivot] = key;//bengin 与 end 相遇,相遇的位置一定是一个坑
QuickSort1(a, left, pivot - 1);
QuickSort1(a, pivot + 1, right);
}
int** combinationSum2(int* candidates, int candidatesSize, int target, int* returnSize, int** returnColumnSizes){ *returnSize = 0;
int *path = (int *)malloc(sizeof(int)*candidatesSize);
int *pathSize = (int *)calloc(1,sizeof(int));
int **result = (int **)malloc(sizeof(int *)*100001);
*returnColumnSizes = (int *)malloc(sizeof(int *)*100001);
int *visited = (int *)calloc(candidatesSize,sizeof(int));
int *sum = (int *)calloc(1,sizeof(int));
QuickSort1(candidates,0,candidatesSize-1);
back(candidates,candidatesSize,target,0,path,pathSize,result,returnColumnSizes,visited,returnSize,sum);
return result;
}
2、C++
class Solution {
public:
vector<vector<int>> result;
vector<int> path;
void back(vector<int>& candidates, int target,int start,int sum,vector<bool> &visited){
if(sum==target){
result.push_back(path);
return;
}
for(int i=start;i<candidates.size();i++){
if(sum+candidates[i]>target){break;}
if(i>0&&candidates[i-1]==candidates[i]&&visited[i-1]==false){continue;}
path.push_back(candidates[i]);
sum += candidates[i];
visited[i] = true;
back(candidates,target,i+1,sum,visited);
visited[i] = false;
sum -= candidates[i];
path.pop_back();
}
}
vector<vector<int>> combinationSum2(vector<int>& candidates, int target) {
sort(candidates.begin(),candidates.end());
vector<bool> visited(candidates.size(),false);
back(candidates,target,0,0,visited);
return result;
}
};
3、JAVA
class Solution {
List<List<Integer>> result = new ArrayList<>();
LinkedList<Integer> path = new LinkedList<>();
public void back(int[] candidates, int target,int start,int sum,boolean[] visited){
if(sum==target){
result.add(new ArrayList(path));
return;
}
for(int i=start;i<candidates.length;i++){
if(sum+candidates[i]>target){break;}
if(i>0&&candidates[i-1]==candidates[i]&&visited[i-1]==false){continue;}
path.addLast(candidates[i]);
visited[i] = true;
sum += candidates[i];
back(candidates,target,i+1,sum,visited);
sum -= candidates[i];
visited[i] = false;
path.removeLast();
}
}
public List<List<Integer>> combinationSum2(int[] candidates, int target) {
Arrays.sort(candidates);
boolean[] visited = new boolean[candidates.length];
Arrays.fill(visited,false);
back(candidates,target,0,0,visited);
return result;
}
}
4、Python
class Solution(object):
def __init__(self):
self.result = []
self.path = []
self.visited = []
def combinationSum2(self, candidates, target):
"""
:type candidates: List[int]
:type target: int
:rtype: List[List[int]]
"""
candidates.sort()
self.visited = [False]*len(candidates)
self.back(candidates,target,0,0)
return self.result def back(self,candidates,target,start,sum):
if sum == target:
self.result.append(self.path[:]);
return
for i in range(start,len(candidates)):
if sum + candidates[i]>target:
break
if i>0 and candidates[i-1]==candidates[i] and self.visited[i-1]==False:
continue
self.path.append(candidates[i])
sum += candidates[i]
self.visited[i] = True
self.back(candidates,target,i+1,sum)
self.visited[i] = False
sum -= candidates[i]
self.path.pop()
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